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4 years ago

Write an equation in standard form of the line passing through the points (3,3) and (-3,5)

Mathematics

1 answer:

Ulleksa [173]4 years ago

6 0

The equation of line passing through the points (3,3) and (-3,5) is:

x+3y=12

Step-by-step explanation:

Given points are:

(x1, y1) = (3,3)

(x2, y2) = (-3, 5)

The general form of slope-intercept form is:

$y=mx+b$

We have to find slope first

$m=\frac{y_2-y_1}{x_2-x_1}\\=\frac{5-3}{-3-3}\\=\frac{2}{-6}\\=-\frac{1}{3}$

Putting the value of m in general form

$y=-\frac{1}{3}x+b$

To find the value of b, putting (3,3) in equation

$3=-\frac{1}{3}(3)+b\\3=-1+b\\b=4$

Putting the values of m and b in general form

$y=-\frac{1}{3}x+4$

Multiplying both sides by 3

$3y=-x+12\\x+3y=12$

The equation of line passing through the points (3,3) and (-3,5) is:

x+3y=12

Keywords: Equation of line, Standard form

Learn more about standard form of equation of line at:

#LearnwithBrainly

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True or false? A correct answer is worth (2 pts). Explain how you know for the additional (2 pts). Using complete sentence for (

PtichkaEL [24]

answer (in words)

FALSE. the coordinate pair (5, 2) is not a solution to the equation $2x+3y=10$ . in order to figure out whether or not the statement is true or false, plug the $x$ and $y$ values from the coordinate pair (5, 2) into the given equation, $2x+3y=10$ . if both sides of the equation end up equal, the coordinate pair is a solution to the equation. if not, the coordinate pair is not a solution to that equation.

(i hope i explained that well enough, i'm better at explaining it algebraically as opposed to putting it into words lol)

answer (algebraic/steps for solving)

first, plug in 5 for $x$ in the equation $2x+3y=10$ .

$2x+3y=10$ ⇒ $2(5)+3y=10$

then plug in 2 for $y$ .

$2(5)+3y=10$ ⇒ $2(5)+3(2)=10$

now your equation is $2(5)+3(2)=10$ . all that's left to do is to simplify. you can do this in whatever order you'd like, but i'll start with multiplying 2 · 5.

$2(5)+3(2)=10$ ⇒ $10 + 3(2) = 10$

multiply 3 · 2.

$10 + 3(2) = 10$ ⇒ $10 + 6 = 10$

add 10 + 6.

$10 + 6 = 10$ ⇒ $16=10$

16 and 10 are not equal, therefore (5, 2) is not a solution to the equation $2x+3y=10$ . in order for a coordinate pair to be the solution to an equation, both sides of the equation need to end up equal after solving and simplifying.

i hope this helps! have a great rest of your day <3

6 0

3 years ago

3/5 of the class were boys. The teacher divided the boys equally into groups so the each group of boys had 1/10 of the number of

Lana71 [14]

I think boys =18
girls=12
boys :x
girls:y
student:z
the number of group for the boys :n
the numberof group for the girls :m
so x=(3/5)*z
y=(2/5)* z
x/y=3/2
3y-2x=0
(1/10)*z*n=(3/5) *z
so n=6
(1/5)*z*m=(2/5)* z
put x=(1/10)*z*6
y=(1/5)*z*2
into 3y-2x=0 and z=30
z=30 so x=(1/10)*30*6=18
y=(1/5)*30*2=12

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3 years ago

What is the square root of 36x to the fourth power?

-BARSIC- [3]

$\sqrt{36x^4}=\sqrt{36}\cdot\sqrt{x^4}=\sqrt{6^2}\cdot\sqrt{(x^2)^2}=6\cdot x^2=\boxed{6x^2}$

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3 years ago

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Fofino [41]

Answer:

264

Step-by-step explanation:

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3 years ago

Please Help With This. What is the equation of the line shown in this graph? Answer your answer in the box.

Margaret [11]

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -2}}\quad ,&{{ -3}})\quad 
% (c,d)
&({{ 3}}\quad ,&{{ -3}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-3-(-3)}{3-(-2)}
\\\\\\
\cfrac{-3+3}{3+2}\implies \cfrac{0}{5}\implies 0$

$\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-3)=0[x-(-2)]
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3 years ago