Question

Write an equation in standard form of the line passing through the points (3,3) and (-3,5)

Answer 1

The equation of line passing through the points (3,3) and (-3,5) is:

x+3y=12

Step-by-step explanation:

Given points are:

(x1, y1) = (3,3)

(x2, y2) = (-3, 5)

The general form of slope-intercept form is:

$y=mx+b$

We have to find slope first

$m=\frac{y_2-y_1}{x_2-x_1}\\=\frac{5-3}{-3-3}\\=\frac{2}{-6}\\=-\frac{1}{3}$

Putting the value of m in general form

$y=-\frac{1}{3}x+b$

To find the value of b, putting (3,3) in equation

$3=-\frac{1}{3}(3)+b\\3=-1+b\\b=4$

Putting the values of m and b in general form

$y=-\frac{1}{3}x+4$

Multiplying both sides by 3

$3y=-x+12\\x+3y=12$

The equation of line passing through the points (3,3) and (-3,5) is:

x+3y=12

Keywords: Equation of line, Standard form

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