Answer:
As per dot plots we see the distribution of prices is close but majority of prices are concentrated in different zones. So MAD would be more similar by the look.
<u>Let's verify</u>
<h3>Neighborhood 1</h3>
<u>Data</u>
- 55, 55, 60, 60, 70, 80, 80, 80, 90, 120
<u>Mean</u>
- (55*2+ 60*2+ 70+ 80*3 + 90+ 120)/10 = 75
<u>MAD</u>
- (20*2+15*2+5+5*3+15+45)/10 = 15
<h3>Neighborhood 2</h3>
<u>Data</u>
- 100, 110, 110, 110, 120, 120, 120, 140, 150, 160
<u>Mean</u>
- (100 + 110*3+ 120*3+ 140 + 150+ 160)/10 = 124
<u>MAD</u>
- (24+14*3+4*3+16*3+16+26+36)/10 = 20.4
As we see the means are too different (75 vs 124) than MADs (15 vs 20.4).
Here is an example I did of the problem hope it helps let me know if you need anything else~!
~<span>Cecildoesscience </span>
18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.
<u>Step-by-step explanation:</u>
Let x = kg of 15% copper alloy
Let y = kg of 60% copper alloy
Since we need to create 90 kg of alloy we know:
x + y = 90
51% of 90 kg = 45.9 kg of copper
So we're interested in creating 45.9 kg of copper
We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:
0.15x + 0.60y = 45.9
but
x + y = 90
x= 90 - y
substituting that value in for x
0.15(90 - y) + 0.60y = 45.9
13.5 - 0.15y + 0.60y = 45.9
0.45y = 32.4
y = 72
Substituting this y value to solve for x gives:
x + y = 90
x= 90-72
x=18
Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.
Perimeter: 2 1/8 + 3 1/2 + 2 1/2 = 7 (1 + 4 + 4)/8 = 7 9/8 = 8 1/8
Hope this will help you!
Answer:
43
Step-by-step explanation:
Using the remainder theorem, that is
The remainder on dividing f(x) by (x - h) is the value of f(h)
here division by (x - 3) hence evaluate f(3) for remainder
f(3) = 3² + 14(3) - 8 = 9 + 42 - 8 = 43 ← remainder
