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3 years ago

Unit rate for travel 250 mild in 5 hours

Mathematics

2 answers:

laila [671]3 years ago

7 0

The unit rate is 50 because you have to divide to get the unit rate

Setler [38]3 years ago

6 0

250 miles in 5 hours can also be written as 250/5 and since you are looking for a unit rate we must make the denominator 1 so we can divide both sides by 5 and get 50/1 in other words the unit rate is
50 miles per hour

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3 years ago

What is the length of the transverse axis (y-2)^2/16 - (x+1)^2/144= 1

Scilla [17]

The length of the transverse axis is 8.

<h3>What is transverse axis length?</h3>

The transverse axis of the hyperbola is the straight line connecting vertices A and A'. The line segment connecting the vertices of a hyperbola is referred to as the transverse axis or AA'.
The hyperbola's equation is expressed as (yk)2b2(xh)2a2=1). The center is (h,k), b defines the transverse axis, and a defines the conjugate axis. The section of a line where a hyperbola's vertices form.

Given the equation of hyperbola: $\frac{(y-2)^{2} }{16}$ $-\frac{(x+1)^{2} }{144 }$ $=1$

Rewrite this equation as $\frac{(y-2)^{2} }{4^{2} }$ $-\frac{(x+1)^{2} }{12^{2} }$ $=1$

When comparing this equation to the common hyperbola equation with a vertical transverse axis is $\frac{(y-k)^{2} }{a^{2} }$ $-\frac{(x+h)^{2} }{b^{2} }$ $=1$

$h = -1$

$k= -2$

$a = 4$

$b = 12$

The length of the transverse axis is $2a = 2*4$

$=8.$

The length of the transverse axis is 8.

To learn more about the length of the transverse axis, refer to:

brainly.com/question/2292250

#SPJ9

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2 years ago

explain how you can use multiplication to find the quotient 3/5 divided by 3/15. then evaluate the expression

Vaselesa [24]

$\frac{3}{5}$ ÷ $\frac{3}{15}$

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3 years ago

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What add's up to 5 and multiplies to -36

Masteriza [31]

X, y - the numbers

The numbers add up to 5 and multiply to -36.
$x+y=5 \\
xy=-36 \\ \\
y=5-x \\
xy=-36 \\ \\
\hbox{substitute 5-x for y in the second equation:} \\
x(5-x)=-36 \\
5x-x^2=-36 \\
-x^2+5x+36=0 \\
-x^2-4x+9x+36=0 \\
-x(x+4)+9(x+4)=0 \\
(-x+9)(x+4)=0 \\
-x+9=0 \ \lor \ x+4=0 \\
x=9 \ \lor \ x=-4 \\ \\
y=5-x \\
y=5-9 \ \lor \ y=5-(-4) \\
y=-4 \ \lor \ y=9 \\ \\
(x,y)=(9,-4) \hbox{ or } (x,y)=(-4,9)$

The numbers are -4 and 9.

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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