The formula of a lateral area of a cylinder:
![LA=2\pi rH](https://tex.z-dn.net/?f=LA%3D2%5Cpi%20rH)
We have r = 9 yd and H = 4 yd. Substitute:
![LA=2\pi(9)(4)=72\pi\ yd^2](https://tex.z-dn.net/?f=LA%3D2%5Cpi%289%29%284%29%3D72%5Cpi%5C%20yd%5E2)
Answer: -9
Step-by-step explanation:
Ok so mean means average so exmple
mean of 1,2,3+5 would be (1+2+3+5)/4
(sum of terms)/(number of terms)=mean so
number of terms=5 since 5 oranges
sum=(46+39+53+61+49)
so mean=(46+39+53+61+49)/5=248/5=49.6
so the answer would be 49.6 (estimateed to be 50)
<h2><u>
Answer with explanation</u>
:</h2>
Let p be the population proportion of parents who had children in grades K-12 were satisfied with the quality of education the students receive.
Set of hypothesis :
![H_0: p=0.43\\\\ H_a:p\neq0.43](https://tex.z-dn.net/?f=H_0%3A%20p%3D0.43%5C%5C%5C%5C%20H_a%3Ap%5Cneq0.43)
Confidence interval for population proportion is given by :-
, where
n= sample size
= sample proportion
and
is the two-tailed z-value for confidence level (c).
As per given ,
Sample size of parents : n= 1085
Number of parents indicated that they were satisfied= 466
Sample proportion : ![\hat{p}=\dfrac{466}{1085}\approx0.429](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%3D%5Cdfrac%7B466%7D%7B1085%7D%5Capprox0.429)
Critical value for 90% confidence interval :
( by z-value table)
Now, the 90% confidence interval :
Thus , the 90% confidence interval: (0.4043, 0.4537).
Since 0.43 lies in 90% confidence interval , it means we do not have enough evidence to reject the null hypothesis .
i.e. We are have no evidence that parents' attitudes toward the quality of education have changed.
Answer:
X4
Step-by-step explanation: