The circumference of the inner circle is 44 ft. The distance between the inner circle and the outer circle is 2 ft. By how many
feet is the circumference of the outer circle greater than the circumference of the inner circle? (Use 3.14 for π)
1 answer:
You should draw a picture to visualize the problem easier.
The circumference of inner circle = 44 ft
That means the radius of the inner circle:
2*pi*r = 44
r = 44/(2pi) = 22/pi
Using the picture you hopefully drew, we see that the radius of the outer circle:
22/pi + 2
To figure out the circumference of the outer circle:
2pi*(22/pi + 2) = 44 + 4pi
So how much bigger is the the circumference of the outer circle than the inner circle?
44 + 4pi - 44 = 4pi
It is 4pi bigger or 4 * (3.14) = 12.56 feet
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