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Finger [1]
3 years ago
9

The circumference of the inner circle is 44 ft. The distance between the inner circle and the outer circle is 2 ft. By how many

feet is the circumference of the outer circle greater than the circumference of the inner circle? (Use 3.14 for π)
Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0
You should draw a picture to visualize the problem easier.

The circumference of inner circle = 44 ft
That means the radius of the inner circle:

2*pi*r = 44
r = 44/(2pi) = 22/pi

Using the picture you hopefully drew, we see that the radius of the outer circle:
22/pi + 2

To figure out the circumference of the outer circle:
2pi*(22/pi + 2) = 44 + 4pi

So how much bigger is the the circumference of the outer circle than the inner circle?

44 + 4pi - 44 = 4pi

It is 4pi bigger or 4 * (3.14) = 12.56 feet
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Answer:

Y=4

Step-by-step explanation:

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step 1 )  8Y = 6Y + 8

step 2 ) isolate the variable to one side 8Y-6Y= 8 =>  2Y = 8

step 3 ) solve for Y 2Y/2 = 8/2

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How can you understand porportions
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That's a portion.

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4 0
2 years ago
The digram shows a triangle
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3 0
8 months ago
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Arisa [49]
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3 years ago
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iogann1982 [59]

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Multiplication property of equality

Step-by-step explanation:

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Required

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