Answer: 42
Step-by-step explanation:
Let A represents the number of freshmen participated in sports and B represents the number of freshmen participated in clubs.
Then , we have given that
Using formula
We have,
Now, the number of students are involved in just sports is given by :-
Hence, 42 students are involved in just sports.
Given Information:
Volume of truck = 15 ft³
Area of base of container = 6 ft²
Required Information:
Height of truck = h = ?
Answer:
Height of truck = h = 2.5 ft
Step-by-step explanation:
The volume of the truck is given by
V = l*w*h
Where l is the length, w is the width, h is the height
The area of the base of container is given by
A = l*w
Where l is the length and w is the width.
Substitute the equation of area into the volume of the truck equation.
V = l*w*h
V = (A)*h
Re-arrange for the height,
h = V/A
h = 15 ft³/6 ft²
h = 2.5 ft
Therefore, the height of the clothing truck is 2.5 ft.
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<u>Step-by-step explanation:</u>
so, is a semi-circle, half a circle, recall a circle has a total of 360°, so half of that will be 180°.
the diameter of that circle is 10, so its radius is half that, or 5.
![\bf \textit{arc's length}\\\\ s=\cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ \theta =180\\ r=5 \end{cases}\implies s=\cfrac{(180)(\pi )(5)}{180}\implies s=5\pi \stackrel{\pi =3.14}{\implies s=15.7}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barc%27s%20length%7D%5C%5C%5C%5C%20s%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20r%7D%7B180%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20%5Ctheta%20%3Dangle~in%5C%5C%20%5Cqquad%20degrees%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20%5Ctheta%20%3D180%5C%5C%20r%3D5%20%5Cend%7Bcases%7D%5Cimplies%20s%3D%5Ccfrac%7B%28180%29%28%5Cpi%20%29%285%29%7D%7B180%7D%5Cimplies%20s%3D5%5Cpi%20%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7B%5Cimplies%20s%3D15.7%7D)
Answer:
Let the MP of 1 article = Rs 1
MP of 15 article = Rs 15
SP of (15+1) articles = 15 x 96/100
= Rs 14.40
CP of 16 article = 14.40/135 x 100
= Rs 32/3
CP of 1 article = 32/3x16
= Rs 2/3
Required % = 1/3 x 3/2 x 100
= 50
