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4 years ago

Can someone answer it

Mathematics

1 answer:

Troyanec [42]4 years ago

3 0

Answer what? This question? Oh, I'm answering it right now. Did you have another question out? Well, I can't see it.

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Tom found some foreign coins in a box. The coins were marked m,a,t,h his uncle told him that each letter on the coin has a diffe

aleksandr82 [10.1K]

Answer:

He will receive $515 for the 17 coins

Step-by-step explanation:

In this question, we are asked to calculate how much will be received for 17 coins , with each coin having a specific value in the US currency.

Obviously, there are four coins, so let’s proceed to get the amount he gets per type of coins.

For the m coin, she has 3 pieces. One m coin has a value of $10, then the amount of coins she makes on the m coins will be 3 * 10 = $30

For the a coin, he has 7 pieces. One m coin has a value of $5, then the amount of coins she makes on the a coins will be 7 * 5 = $35

For the t coin, he has 5 pieces. One t coin has a value of $50, then the amount of coins she makes on the t coins will be 5 * 50= $250

For the h coin, she has 2 pieces. One h coin has a value of $100, then the amount of coins she makes on the h coins will be 2* 100 = $200

The total amount made on the 17 coins would thus be mathematically equal to;

Amount made on m coins + Amount made on a coins + Amount made on t coins + Amount made on h coins

The total amount = $30 + $35 + $250 + $200 = $515

6 0

4 years ago

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Find the surface area of a box measuring 4 inches long 3 inches wide and 6 inches tall

Rufina [12.5K]

4*3

12*6

hope it help

3 0

3 years ago

Select the quadratic equation that has roots x=8 and x=-5

stellarik [79]

Step-by-step explanation:

Since, x=8 and x=-5 are the roots.

Therefore, (x - 8) & (x - 5) will be factors.

Hence, required quadratic equation can be given as:

$(x - 8)(x - 5) =0 \\ \\ \therefore {x}^{2} + ( - 8 - 5) x+ ( - 8) \times ( - 5) = 0 \\ \\ \therefore {x}^{2} + ( - 13) x+ 40= 0 \\ \\ \huge \red{ \boxed{ \therefore {x}^{2} - 13x+ 40= 0 }} \\ is \: the \: required \: quadratic \: equation.$

5 0

3 years ago

Solve the equation on the interval 0 less than or equals theta less than 2 pi .0≤θ<2π. secant StartFraction 5 theta Over 4 En

qaws [65]

Answer: 4π/15, 4π/3 and 28π/15 (in radians)

Step-by-step explanation:

$sec 5\theta/4 =2$

Recall that $sec \theta = 1/cos \theta$

$1/cos (5\theta/4) =2$

$cos (5\theta/4) =1/2$

$Cos^{-1}$ $\frac{1}{2}$ = $5\theta/4$

This implies that

$\mp60+360n=5\theta/4$

$\theta=4/5(\mp60+360n)= \mp48+288n$

$When n=0, \theta=48$

$When n=1, \theta=240, 336$

Therefore the values of $\theta$ between 0 and 2π are 48, 240 and 336. (All in degrees)

48 degrees= 4π/15 rad

240 degrees =4π/3 rad

336 degrees = 28π/15 rad

5 0

3 years ago

What is 0.02 to the fifth power equal?

Lyrx [107]

3.2E-9

A bit complicated, so PLEASE don't ask for an explanation

5 0

4 years ago

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