Answer:
2
litres or 2.5 litres
Step-by-step explanation:
From the question, 9 fruit juice bottles contain 4 litres of fruit juice. Therefore, to find how many litres of fruit juice would be contained in 5 fruit juice bottles, you multiply 5 by 4 litres and you divide the product by 9.
i.e. Let the quantity of the fruit juice for 5 bottles be x.
9 juice bottles ===> 4 litres
5 juice bottles ===> x
∴x = 
x = 
x = 
x = 2.5 litres or 2 litres
Hope this helps!!!
To solve this question, you need to first look at the total amount of birds and then at the percentage of the blue jays that fed on the bird feeder out of all the other birds.
To calculate the total you add them all together:
59+68+12+1 = 140 birds
Then the percentages of the blue jays that fed on his bird feeder are:
59/140 *100 = 42.143%
You want to see how many blue jays we can expect to see out of 300 birds.
So you divide 300 by 100 to see what 1% is = 3 birds
Then you multiply this amount (1% = 3 birds) by 42.134% which is the percentage of blue jays we can expect to see out of the 300 birds.
3*42.134 = 126.43
You round this off to 126 because you cant expect to see half a bird. Even if the answer had been 126.9, you would have rounded it of to 126 because no matter how close it is to the next whole number; you either have a whole bird or you don't.
Final Answer = 126
So the height will equal 95.50 inches.
So if you double the height the volume is 1800cm3 and that is double the original volume
And if you double the height the volume is 3600cm3 and that is the triple the original volume
9514 1404 393
Answer:
D.) a+2b
Step-by-step explanation:
The integers 'a' and 'b' can be any, so you can choose a couple and evaluate these expressions to see what you get. For example, we can let a=1 and b=0. For these values, the offered expressions evaluate to ...
A) 3(0) = 0 . . . even
B) 1 +3 = 4 . . . even
C) 2(1+0) = 2 . . . even
D) 1 +2(0) = 1 . . . odd
_____
<em>Additional comment</em>
These rules apply to even/odd:
- odd × odd = odd
- odd × even = even
- even × even = even
- odd + odd = even
- odd + even = odd
- even + even = even
Then A is (odd)(even) = even; B is (odd)+(odd) = even; C is (even)(whatever) = even; D = (odd)+(even) = odd.
Answer: -5100
<u>Step-by-step explanation:</u>
![\sum^4_1[100(-4)^{n-1}]\qquad \rightarrow \qquad a_1=100\ \text{and r = -4}\\\\\\S_n=\dfrac{a_1(1-r^n)}{1-r}\\\\\\\\S_4=\dfrac{100(1-(-4)^4)}{1-(-4)}\\\\\\.\quad=\dfrac{100(1-256)}{1+4}\\\\\\.\quad=\dfrac{100(-255)}{5}\\\\.\quad=20(-255)\\\\.\quad=-5100\\](https://tex.z-dn.net/?f=%5Csum%5E4_1%5B100%28-4%29%5E%7Bn-1%7D%5D%5Cqquad%20%5Crightarrow%20%5Cqquad%20a_1%3D100%5C%20%5Ctext%7Band%20r%20%3D%20-4%7D%5C%5C%5C%5C%5C%5CS_n%3D%5Cdfrac%7Ba_1%281-r%5En%29%7D%7B1-r%7D%5C%5C%5C%5C%5C%5C%5C%5CS_4%3D%5Cdfrac%7B100%281-%28-4%29%5E4%29%7D%7B1-%28-4%29%7D%5C%5C%5C%5C%5C%5C.%5Cquad%3D%5Cdfrac%7B100%281-256%29%7D%7B1%2B4%7D%5C%5C%5C%5C%5C%5C.%5Cquad%3D%5Cdfrac%7B100%28-255%29%7D%7B5%7D%5C%5C%5C%5C.%5Cquad%3D20%28-255%29%5C%5C%5C%5C.%5Cquad%3D-5100%5C%5C)
