The distance coveredby a car in3x hours is27x3_9x²+3x. Find the rate of the car
1 answer:
Answer:
<h3>9x²-3x+1</h3>
Step-by-step explanation:
The rate of the change of the car is is its speed.
Speed = distance/time
Given
Distance = 27x³-9x²+3x
Time = 3x hours
Speed = 27x³-9x²+3x/3x
factor out 3x from the numerator:
Speed = 3x(9x²-3x+1)/3x
Speed = 9x²-3x+1
Hence the rate of the car is 9x²-3x+1
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Answer:
16
Step-by-step explanation:
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-> c²= g²+b²
c²= 20²+21²
c²= 841
c=V841
c=29
-> triangle BCG is right
2.
cos B= 20/29
tan B= 21/20
sin B= 21/29
sin G= 20/29
cos G= 21/29
tan G= 20/21
Um 100 idk BUT IM JUST ANSWERING
Answer:
Where is the rest of the equation?
Step-by-step explanation:
Answer:
the last MNO and PQR is the correct answer
