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boyakko [2]
3 years ago
13

Which of the following is a perfect square trinomial?

Mathematics
2 answers:
yanalaym [24]3 years ago
6 0
Your answer is D. 16x² - 56xy + 49y².

A perfect square trinomial is the result of a squared binomial, like (a + b)². Using this example, the perfect square trinomial would be a² + 2ab + b², as that is what you get when you expand the brackets.

Therefore, to determine which of these is a perfect square trinomial, we have to see if it can be factorised into the form (a + b)².

I did this by first square rooting the 16x² and 49y² to get 4x and 7y as our two terms in the brackets. We automatically know the answer isn't A or B as you cannot have a negative square number.

Now that we know the brackets are (4x + 7y)², we can expand to find out what the middle term is, so:

(4x + 7y)(4x + 7y)
= 16x² + (7y × 4x) + (7y × 4x) + 49y²
= 16x² + 28xy + 28xy + 49y²
= 16x² + 56xy + 49y².

So we know that the middle number is 56xy. Now we assumed that it was (4x + 7y)², but the same 16x² and 49y² can also be formed by (4x - 7y)², and expanding this bracket turns the +56xy into -56xy, forming option D, 16x² - 56xy + 49y².

I hope this helps!
AVprozaik [17]3 years ago
6 0

Answer:

It would have to be the last choice

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torisob [31]

Let's solve your inequality step-by-step.

5m<6m+6

Step 1: Subtract 6m from both sides.

5m−6m<6m+6−6m

−m<6

Step 2: Divide both sides by -1.

−m / −1 < 6 / −1

m>−6

Answer:

m>−6

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3 years ago
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4 0
2 years ago
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zaharov [31]

Answer:

As shown in picture, the area is divided into 4 parts: 3 triangles and 1 rectangles.

Total area:

A = smallest triangle + medium triangle + largest triangle + rectangle

   = 2 x 2 x 1/2 + 2 x 6 x 1/2 + 4 x (2 + 2 + 6) x 1/2 + 2 x 2

   = 2 + 6 + 20 + 4

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8 0
3 years ago
Given: <br> ΔABC, m∠C = 90º, m∠B = 30º<br> CM - angle bisector<br><br> Find: m∠AMC
SashulF [63]

Answer:

75°

Step-by-step explanation:

1. Consider right triangle ABC. In this triangle

m∠C = 90º and CM - angle bisector.

If CM is angle C bisector, then

m∠ACM = m∠MCB = 45º

2. Consider triangle CMB. The sum of the measures of all interior angles of the triangle is always 180°, then

m∠MCB + m∠CBM + m∠BMC = 180°,

m∠BMC = 180° - 45° - 30°

m∠BMC = 105°

3. Angles AMC and BMC are supplementary angles, so

m∠AMC + m∠BMC = 180°

m∠AMC = 180° - 105°

m∠AMC = 75°

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3 years ago
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Evgesh-ka [11]

Answer: c

Step-by-step explanation:

4 0
3 years ago
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