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FinnZ [79.3K]
3 years ago
11

Jim's Camera shop sells two high-end cameras, the Sky Eagle and Horizon. The demands for these two cameras are as follows: DS =

demand for the Sky Eagle, PS is the selling price of the Sky Eagle, DH is the demand for the Horizon, and PH is the selling price of the Horizon.
DS = 229 − 0.60PS + 0.35PH
DH = 269 + 0.10PS − 0.64PH
The store wishes to determine the selling price that maximizes revenue for these two products. Develop the revenue function for these two models. (Enter your answer in terms of
PS and PH.)
revenue =
Mathematics
1 answer:
BartSMP [9]3 years ago
5 0

The revenue is given by the product of the price and the demand function

  • The revenue function for Sky Eagle is <u>RS = 229·PS - 0.60·PS² + 0.35·PS·PH</u>.
  • The revenue function for Horizon is <u>RH = 269·PH + 0.10·PS·PH - 0.64·PH²</u>.

Reasons:

The given parameters are;

The demand function for the Sky Eagle, DS = 229 - 0.60·PS + 0.35·PH

The demand function for the Horizon, DH = 269 + 0.10·PS - 0.64·PH

The above demand functions gives the quantity demanded

Therefore, the revenue function is given by the product of the price and the demand function as follows;

RS = PS × DS = PS × (229 - 0.60·PS + 0.35·PH) = 229·PS - 0.60·PS² + 0.35·PS·PH

The revenue for Sky Eagle <u>RS = 229·PS - 0.60·PS² + 0.35·PS·PH</u>

<u />

Revenue for Horizon is found as follows;

RH = PH ×(269 + 0.10·PS - 0.64·PH) = 269·PH + 0.10·PS·PH - 0.64·PH²

The revenue for Horizon, <u>RH =  269·PH + 0.10·PS·PH - 0.64·PH²</u>

Learn more demand function here:

brainly.com/question/16888880

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Answer:

Area = 21 unit²

Step-by-step explanation:

We have one point of triangle = (0,0)

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when x = 3,      y =  3²−16  = 9 -16 = -7  , point is (3,-7)

when x = -3,      y =  (-3)²−16  = 9 -16 = -7  , point is (-3,-7)

We need to find area of triangle with points  (0,0), (3,-7) and (-3,-7).

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         Area =\frac{1}{2}\begin{vmatrix}0 & 0 & 1\\ 3 & -7 & 1\\ -3 & -7 & 1\end{vmatrix}

  Area = \frac{1}{2}\left ( 0(-7\times 1-(1\times -7))-0(3\times 1-(1\times -3))+1(3\times -7-(-3\times -7)\right )\\\\Area =\frac{1}{2}(-21-21)=-21=21unit^2

Area = 21 unit²

5 0
3 years ago
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13

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8 less than six times a number y
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Assume that the wavelengths of photosynthetically active radiations (PAR) are uniformly distributed at integer nanometers in the
trasher [3.6K]

Answer:

Mean=685

Variance=36.7

Step-by-step explanation:

The mean of uniform discrete distribution can be expressed as the average of the boundaries

mean=( b+a)/2

The variance of uniform discrete distribution can be expressed as the difference of the boundaries decreased by 1 and squared, decreased by 1 and divided by 12.

σ²=[(b-a+1)^2 - 1]/12

We were given the wavelength from from 675 to 695 nm which means

a= 675, b= 695

We can now calculate the mean by using the expresion below

mean=( b+a)/2

Mean=( 675 + 695)/2

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The variance can be calculated by using the expression below

σ²=[(b-a+1)^2 - 1]/12

σ²=[(695-675+1)^2 -1]/12

σ²=440/12

σ²=36.7

Therefore, the the mean and variance, of the wavelength distribution for this radiation are 685 and 36.7 respectively

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