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kipiarov [429]
3 years ago
10

Simplify.

Mathematics
1 answer:
Hoochie [10]3 years ago
7 0
C might be the answer
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Can someone help me on this math problem PLEASE
egoroff_w [7]

Answer:

QR perpendicular to PT

PR^Q=SR^T=90°

also ANGLES (QPR= STR

7 0
3 years ago
12x15y=4140; x+y= ? <br> solve.
Semenov [28]

Answer: The number of $12 tickets and $15 sold are 120 and 180 respectively.

Step-by-step explanation:

The given equation is:

12x + 15y = 4140             .....(1)

Where,

x stands for $12 tickets and y stands for $15 tickets

According to the question:

x + y = 300           ....(2)

Now solving equation 1 and 2.

From equation 2:

x = 300 - y

Now putting this expression in equation 1.

12x + 15y = 4140

12(300 - y) + 15y = 4140

3600 - 12y + 15y = 4140

3600 + 3y = 4140

3y = 4140 - 3600

3y = 540

y = 180

And,

x = 300 - y = 300 - 180 = 120

The number of $12 tickets sold = x = 120

The number of $15 tickets sold = y = 180

Thus, the number of $12 tickets and $15 sold are 120 and 180 respectively.

4 0
3 years ago
Evaluate. 75-2(9-5)²+2³
Andreyy89
75-2(9-5)^2+2^3

First, solve the parentheses:

75-2(4)^2+2^3

Next, the exponential terms

75-2(16)+8

Solve the multiplication:

75-32+8

Add and subtract:

51

5 0
1 year ago
Kiran and his cousin work during the summer for a landscaping company. Kiran's cousin has been working for the company longer, s
Marta_Voda [28]
Kiran earns $8.50 per hour.

Let x represent Kiran's pay.  He worked 23 hours last week, so his pay would be given by 23x.

Kiran's cousin is paid 30% more.  30% = 30/100 = 0.3.  We add this to the x per hour that Kiran is paid:

x + 0.3x = 1.3x

This is multiplied by 27, since Kiran's cousin works 27 hours:
27(1.3x)

This gives us the following equation:
23x + 27(1.3x) = 493.85
23x + 35.1x = 493.85
58.1x = 493.85

Divide both sides by 58.1:
58.1x/58.1 = 493.85/58.1
x = 8.5

Thus Kiran earns 8.50 per hour.
8 0
3 years ago
Reduced form of 2ab^2-a^2 b^2/5
Ket [755]

Answer:

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

Step-by-step explanation:

Given the expression

2ab^2-\frac{a^2b^2}{5}

\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}

2ab^2-\frac{a^2b^2}{5}=\frac{2ab^2\cdot \:5}{5}-\frac{a^2b^2}{5}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

                 =\frac{2ab^2\cdot \:5-a^2b^2}{5}

                 =\frac{10ab^2-a^2b^2}{5}

Thus,

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

7 0
3 years ago
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