What type of function is shown above?

Solving Equations<br> ve<br> x + 14 = 7x + 32 - 3x

Mkey [24]

Answer:

-6

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x+14=7x+32−3x

x+14=7x+32+−3x

x+14=(7x+−3x)+(32)(Combine Like Terms)

x+14=4x+32

Step 2: Subtract 4x from both sides.

x+14−4x=4x+32−4x

−3x+14=32

Step 3: Subtract 14 from both sides.

−3x+14−14=32−14

−3x=18

Step 4: Divide both sides by -3.

−3x/−3=18/−3

x=−6

5 0

3 years ago

To simplify5(2x-7) use distributive property

sveta [45]

Answer:

10×-35

Step-by-step explanation:

5×2=10

5×7=35

So the answer is 10x-35

8 0

3 years ago

What is 7/35 converted into a decimal??

zheka24 [161]

Answer:

0.2

Step-by-step explanation:

it works out to be 0.2 as a decimal and 20% as a percentage.

6 0

3 years ago

Read 2 more answers

3 of 8<br> The area of a circle is 16.71cm2.<br> Find the length of the radius rounded to 2 DP.

Cerrena [4.2K]

Answer:

Radius = 2.31 cm

Step-by-step explanation:

Area of circle = 16.71 square centimeters

$\pi r^2 = 16.71 \\3.14r^2=16.71\\r^2=\frac{16.71}{3.14}\\r^2=5.32\\\sqrt{r^2}=\sqrt{5.32}\\r=2.306$

Radius of circle = 2.31 centimeter

6 0

3 years ago

(Uniform) Suppose X follows a continuous uniform distribution from 4 to 11. (a) Write down the PDF of X. (b) Find P(X ≤ 7). Roun

love history [14]

Answer:

a) $f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

b) $P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

c) $P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

d) $P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

Step-by-step explanation:

For this case we assume that the random variable X follows this distribution:

$X \sim Unif (a=4, b =11)$

Part a

The probability density function is given by the following expression:

$f(x) = \frac{1}{b-a} , a \leq x \leq b$

$f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

Part b

We want this probability:

$P(X \leq 7)$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}= \frac{x-4}{11-4}$

And replacing we got:

$P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

Part c

We want this probability:

$P(5 < X \leq 7)$

And we can use the CDF again and we have:

$P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

Part d

We want this conditional probabilty:

$P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

7 0

3 years ago