Question

Reduced form of 2ab^2-a^2 b^2/5

Answer 1

Answer:

$2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}$

Step-by-step explanation:

Given the expression

$2ab^2-\frac{a^2b^2}{5}$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}$

$2ab^2-\frac{a^2b^2}{5}=\frac{2ab^2\cdot \:5}{5}-\frac{a^2b^2}{5}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

                 $=\frac{2ab^2\cdot \:5-a^2b^2}{5}$

                 $=\frac{10ab^2-a^2b^2}{5}$

Thus,

$2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}$