Answer:
D
Explanation:
Seeing as the gene is dominate, the hair would still be white evening it's Ww. For the hair to be a different color both parent would need a recessive gene (w), though neither does, meaning all the kids would have white hair.
C. How long does it take a paper bag to break down?
Answer:
Decomposers
Explanation:
The diagram in this question illustrates a food web, which is a series of interlinked food chains in an ecosystem. In a food chain as depicted in the image, the arrows point to the organism that feeds on another organism. For example, an arrow is pointing from Idaho fescue to an Elk meaning that the elk will feed on that plant.
Different trophic levels constituting organisms exists in the food web including; producers (plants), primary consumers, secondary consumers, tertiary consumers etc. However, as observed in the image, a general arrow carrying along all the organism is pointing towards the organism in the question mark. This organism is called DECOMPOSER.
A decomposer, usually a microorganism, is an organism that breaks down dead organisms and returns the nutrient to the soil for recycling. All organisms in the food web will eventually die and when they do, they'll be decomposed by a decomposer. This is why the arrow pointing towards the decomposers include all organisms.
Answer:
biologists have a 14ft john boat with trolling motor for sale or trade
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
