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denis-greek [22]
2 years ago
9

What is longer: a mile or a kilometer?

Mathematics
1 answer:
kotykmax [81]2 years ago
5 0
A miler is longer than a kilometer.
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PLZ HURRY IT'S URGENT!!
abruzzese [7]

Answer:

t≥2

Step-by-step explanation:

because you need at least 2 touchdowns, t must be equal to 2 or more (greater) than 2.

3 0
2 years ago
-2|x-4|+7=-3 how do i solve this absolute value problem
ira [324]
Let's do this step by step:
Subtract both sides by 7
-2|x-4|= -10
Divide each side by -2
|x-4|= 5
Now since this is an absolute value equation, you will have two answers. This means you make the equation both positive and negative.
X-4= 5and -(x-4)= 5
Solve for x for both
X-4= 5: add four on both sides
X= 9
-x+ 4= 5: subtract 4 and divide by -1
X= -1
So your answer is: X= -1 , 9
4 0
3 years ago
1.The equation of line CD is (y−3) = − 2 (x − 4). What is the slope of a line perpendicular to line CD? 2.The equation of line A
gogolik [260]
So here's how to do it,
slope intercept form is y=mx+b
m is the slope, b is the y- intercept, X is your unknown variable.

you need to solve to get y by its self to get your slope.

for perpendicular lines flip the slope

ex 1, smy=2x+6 --- slope of a perpendicular line will be 1/2

ex 2, y=3/2+8 ---8 perpendicular lien would have a slope of 2/3

parallel lines have the same slope so any equation with with the same slope will be parallel if it has the same degree.

ex. y=2x+14 is parallel to y= 2x+56

slope can be found using the following formula if you have two sets of points on the same line

m= y2-y1 ÷ X2 - X1
5 0
2 years ago
Read 2 more answers
Need help, please, please.
Ber [7]
-66 is the 27th term.

You have a function in terms of n. Recall that n is the nth term in the sequence.
Substitute n = 27 into the equation to find the 27th term.

a₂₇ = -10 + (27 + 1)(-2) = -10 + (28)(-2) = -10 - 56 = -66
3 0
2 years ago
Use the identity x3+y3+z3−3xyz=(x+y+z)(x2+y2+z2−xy−yz−zx) to determine the value of the sum of three integers given: the sum of
fenix001 [56]

ffn

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx))

the sum of their squares is 110, So x^2+y^2 + z^2= 110

the sum of their cubes is 684, so  x^3+y^3 + z^3= 684

the product of the three integers is 210, so xyz= 210

the sum of any two products (xy+yz+zx) is 107

Now we plug in all the values in the identity

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx))

684 - 3(210) = (x+y+z)(110-107)

684 - 630 = (x+y+z)(3)

54 = 3(x+y+z)

Divide by 3 on both sides

18 = x+y+z

the value of the sum of three integers is 18

3 0
3 years ago
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