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3 years ago

What is the sum? 4(^5sqrt x^2y)+3(^5sqrt x^2y)

Mathematics

2 answers:

miskamm [114]3 years ago

8 0

Third one is your answer

Lorico [155]3 years ago

6 0

Answer:

$4( \sqrt[5]{ {x}^{2} y} ) + 3( \sqrt[5]{ {x}^{2}y } ) \\$

factorise out the 5th root of x²y :

$= \sqrt[5]{ {x}^{2}y } (4 + 3) \\ = 7( \sqrt[5]{ {x}^{2} y} )$

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On a certain hot summer day, 481 people used the public swimming pool. The daily prices are 1.25 for children and 2.25 for adult

spayn [35]

Answer:the number of children that swam in the public pool that day is 222

the number of adult that swam in the public pool that day is 259

Step-by-step explanation:

Let x represent the number of children that swam in the public pool that day.

Let y represent the number of adult that swam in the public pool that day.

On a certain hot summer day, 481 people used the public swimming pool. This means that

x + y = 481

The daily prices are 1.25 for children and 2.25 for adults. The receipts for admission totaled to 86.25. This means that

1.25x + 2.25y = 860.25 - - - - - - - -1

Substituting x = 481 - y into equation 1, it becomes

1.25(481 - y) + 2.25y = 860.25

601.25 - 1.25y + 2.25y = 860.25

- 1.25y + 2.25y = 860.25 - 601.25

y = 259

Substituting y = 259 into x = 481 - y, it becomes

x = 481 - 259

x = 222

8 0

3 years ago

If the nth term of an AP is (7-4n) then its common difference is

Hitman42 [59]

Given nth term of an AP = 7-4n

Put n = 1 then t1 = 7-4(1) = 7-4 = 3

Put n = 2 then t2 =7-4(2) = 7-8 = -1

Common difference = t2-t1 = -1-3 = -4

3 0

3 years ago

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

5 0

3 years ago

The graph below does not represent a function. Explain why.

Simora [160]

Notice how points T and Z are vertically aligned, or vertically lined up. This is where the graph fails the vertical line test.

The input x = 2 leads to the outputs y = 3 and y = 5 (which are the y coordinates of points Z and T in that order).

A function is only possible when any given input leads to <u>exactly one</u> output only. It would be like saying "the conversion function from Celsius to Fahrenheit has 0 degrees C convert to both 32 degrees F and 50 degrees F at the same time". But such a statement makes no sense and it's not useful. So this is one example of why having one output makes sense for a function.

In short, we need one output for any given input. But the input x = 2 leads to more than one output. That's why we don't have a function.

6 0

3 years ago

6 plates and 5 cups cost 23.80 dollars. 7 plates and 6 cups cost 28.00 dollars. Each plate costs the same amount as the other pl

MrRa [10]

Answer:

c = $1.4

p = $2.8

Step-by-step explanation:

two equations can be derived from the question

6p + 5c = 23.80 equation 1

7p + 6c = 28 equation 2

p = plates

c - cups

multiply equation 1 by 7 and equation 2 by 6

42p + 35c = 166.60 equation 3

42p + 36c = 168 equation 4

subtract equation 3 from 4

c = 1.4

substitute for c in equation 1

6p + 5(1.4) = 23.80

p = (23.80 - 7) / 6

p = 2.8

6 0

2 years ago