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2 years ago

What is the sum? 4(^5sqrt x^2y)+3(^5sqrt x^2y)

Mathematics

2 answers:

miskamm [114]2 years ago

8 0

Third one is your answer

Lorico [155]2 years ago

6 0

Answer:

$4( \sqrt[5]{ {x}^{2} y} ) + 3( \sqrt[5]{ {x}^{2}y } ) \\$

factorise out the 5th root of x²y :

$= \sqrt[5]{ {x}^{2}y } (4 + 3) \\ = 7( \sqrt[5]{ {x}^{2} y} )$

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I do not know how to solve this problem or know what to do with the exponents

horsena [70]

K, remember
(ab)/(cd)=(a/c)(b/d) or whatever
also
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}= \frac{1}{x^m}$
and
$x^ \frac{m}{n}= \sqrt[n]{x^m}$
and
$( \frac{x}{y} )^m= \frac{x^m}{y^m}$
and
$(x^m)^n=x^{mn}$
and
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)

so
$( \frac{-7x^ \frac{3}{2} }{5y^4} )^{-2}$ =
$( \frac{-7}{5} )^{-2}( \frac{x^ \frac{3}{2} }{y^4} )^{-2}$ =
$( \frac{(-7)^{-2}}{5^{-2}} )( \frac{(x^ \frac{3}{2})^{-2} }{(y^4)^{-2}} )$ =
$( \frac{ \frac{1}{(-7)^2} }{ \frac{1}{5^2} } )( \frac{x^ \frac{-6}{2} }{y^{-8}} )$ =
$( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{(x^{-3}) }{\frac{1}{y^8}} )$
$( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{\frac{1}{x^3} }{\frac{1}{y^8}} )$ =
$(\frac{25}{49} )( \frac{y^8}{x^3}$ =
$\frac{25y^8}{49x^3}$

4 0

2 years ago

Combine the like terms to create an equivalent expression <br> 4z- (-3z)

NNADVOKAT [17]

Answer:

Step-by-step explanation:

subtracting a negative is like adding

$4z - (-3z)\\4z+3z\\7z$

4 0

3 years ago

Which of the tables represents a function? Help please i’ll mark brainliest

Helga [31]

Answer:

Table B

Step-by-step explanation:

If you see any number in the input being used more than once, it is not a function. If all numbers of the input are different, it is a function.

Only Table B is a function since all input numbers are different.

5 0

2 years ago

Hi what is the answer for a+5d+3x

sattari [20]

Well I tried doing it but depends what your trying to do with the equation but I got
x= -a/3 - 5d/3

3 0

3 years ago

If i= the square root of -1 what is the value of i^3

BARSIC [14]

i =√-1

i^2 = -1

i^3

= i^2 * i

= -1√-1

= - √-1

5 0

2 years ago