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mart [117]
3 years ago
10

3(n-5)-2(n+8)=11 solve

Mathematics
2 answers:
ololo11 [35]3 years ago
6 0

Answer:

n= 42

Step-by-step explanation:

Given expression is: 3(n-5)-2(n+8)=11  

Now, first of all we will multiply the numbers which are outside the brackets to the numbers inside. Which will become:  

3n-15 - 2n - 16 = 11

Next the second step is to the change the positions. The numbers that are multiplied by n will be together:  

3n - 2n -15 - 16 = 11

Finally, by solving the above equation. We get:

n - 31= 11

n = 11+ 31  

n= 42

Required answer is n = 42

Butoxors [25]3 years ago
3 0

Answer:

n=42

Step-by-step explanation:

The first step is to open the brackets by multiplying the vale before the brackets to the values inside the brackets giving attention to the signs which gives:

3n-15-2n-16=11

Then we collect like terms together.

3n-2n-15-16=11

evaluating the above equation we get

n-31=11

n=11+31

=42

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kipiarov [429]

Answer:

The distance of the playground is 540m

Step-by-step explanation:

Here, we are interested in calculating the length of the playground given the information in the question.

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Now, to find the length of the track, we add the distance covered plus the distance uncovered. Mathematically that would be 960m + 120m = 1,080m

In the last part of the question, we are told that the track is twice as long as the playground. This means that the length of the playground or the distance of the playground is 1080/2 = 540 m

4 0
3 years ago
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ArbitrLikvidat [17]

Answer:

24.075, 24.008, 21.605, 21.048

6 0
3 years ago
Expressed as a product of its prime factors in index form, a number N is
Elena-2011 [213]

<u>ANSWER</u>



5N^2=3^{2} \times 5^{5} \times x^{6}



<u>EXPLANATION</u>


N=3\times5^2 \times x^3.


5N^2=5(3\times5^2 \times x^3)^2


Recall this property of exponents;


(a^m)^2=a^{m} \times a^m



So our product becomes;


5N^2=5(3\times5^2 \times x^3) \times (3\times5^2 \times x^3)



5N^2=5\times 3\times 3 \times 5^2 \times 5^2 \times x^3 \times x^3


5N^2=3\times 3\times 5 \times 5^2 \times 5^2 \times x^3 \times x^3



Recall this law of exponents:


a^m \times a^n =a ^{m+n}


5N^2=3^{1+1} \times 5^{1+2+2} \times x^{3+3}


5N^2=3^{2} \times 5^{5} \times x^{6}




7 0
3 years ago
Please help, picture attached.
igomit [66]

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part b = 7

Step-by-step explanation:

for part a it is a percentage for the number 8 so you do part divided by the whole time 100 to get teh perecentagepart b is the number with the highest pick rate so it has the most likly  choice of being picked.

3 0
3 years ago
Solve the equation.<br><br><img src="https://tex.z-dn.net/?f=%5Csqrt%7By%5E%7B2%7D%20-20y%2B100%20%7D%3D%20y-10" id="TexFormula1
Gelneren [198K]

Notice that

y² - 20y + 100 = y² - 2•10y + 10² = (y - 10)²

Then

√(y² - 20y + 100) = y - 10

is equivalent to

√((y - 10)²) = y - 10

|y - 10| = y - 10

If y ≥ 10, then |y - 10| = y - 10, and

y - 10 = y - 10   ⇒   0 = 0

so there are infinitely many solutions, y ≥ 10.

Otherwise, if y < 10, then |y - 10| = -(y - 10), and

-(y - 10) = y - 10   ⇒   10 = -10

which is false, so there are no solutions in this case.

3 0
2 years ago
Read 2 more answers
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