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mart [117]
3 years ago
10

3(n-5)-2(n+8)=11 solve

Mathematics
2 answers:
ololo11 [35]3 years ago
6 0

Answer:

n= 42

Step-by-step explanation:

Given expression is: 3(n-5)-2(n+8)=11  

Now, first of all we will multiply the numbers which are outside the brackets to the numbers inside. Which will become:  

3n-15 - 2n - 16 = 11

Next the second step is to the change the positions. The numbers that are multiplied by n will be together:  

3n - 2n -15 - 16 = 11

Finally, by solving the above equation. We get:

n - 31= 11

n = 11+ 31  

n= 42

Required answer is n = 42

Butoxors [25]3 years ago
3 0

Answer:

n=42

Step-by-step explanation:

The first step is to open the brackets by multiplying the vale before the brackets to the values inside the brackets giving attention to the signs which gives:

3n-15-2n-16=11

Then we collect like terms together.

3n-2n-15-16=11

evaluating the above equation we get

n-31=11

n=11+31

=42

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Suppose that two teams play a series of games that ends when one of them has won ???? games. Also suppose that each game played
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Answer:

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(b) 6p⁴ - 12p³ + 3p² + 3p + 3; d²/dp² E(X) at p = 1/2 is less than 0

Step-by-step explanation:

(a) when i = 2, the expected number of played games will be:

E(X) = 2[p² + (1-p)²] + 3[2p² (1-p) + 2p(1-p)²] = 2[p²+1-2p+p²] + 3[2p²-2p³+2p(1-2p+p²)] = 2[2p²-2p+1] + 3[2p² - 2p³+2p-4p²+2p³] =  4p²-4p+2-6p²+6p = -2p²+2p+2.

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(b) when i = 3;

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Simplification and rearrangement lead to:

E(X) = 6p⁴-12p³+3p²+3p+3

if p = 1/2, then:

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Therefore, E(X) is maximized.

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