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kupik [55]
3 years ago
10

Determine the area of the given figure: .

Mathematics
1 answer:
Aneli [31]3 years ago
5 0
Which given figure ???
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What is the opposite of 3.82
BigorU [14]
The Opposite of 3.82 is -3.82. It's like you saying what is the inverse of 3.82.
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Ryan spent $26.32 on 8 gallons of gas. How much would he spend for 20 gallons?
nalin [4]
$65.80

$26.32/8=$3.29 for a gallon
$3.29 x 20 = $65.80.

Hope this helps
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Find The Value Of X When 6-2x = 6x-10x+6. The Value Is
Natasha_Volkova [10]

Answer:

x = 0

Step-by-step explanation:

6 - 2x = 6x - 10x + 6

1. Isolate the variable (x)

  • Add 2x to both sides

    6 - 2x = 6x - 10x + 6 -> 6 = 6x - 10x + 2x + 6

  • Subtract 6 from both sides

    6x - 10x + 2x + 6 -> 0 = 6x - 10x + 2x

2. Combine like terms

      0 = 6x - 10x + 2x -> 0 = -2x

3. Solve

  • Divide both sides by -2

       0 = x

*Note: 0 divided by anything is 0 so 0/-2 is 0

(unless it is 0/0 which equals 1)

6 0
3 years ago
Another way to write 9 x 200
Katyanochek1 [597]
200+200+200+200+200+200+200+200+200
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A small town has 2000 families. The average number of children per family is mu = 2.5, with a standard deviation sigma = 1.7. A
Nikitich [7]

Answer:

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where \mu=2.5 and \sigma=1.7

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And for this case the standard error would be:

\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where \mu=2.5 and \sigma=1.7

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And for this case the standard error would be:

\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125

6 0
3 years ago
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