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lianna [129]
3 years ago
6

Two cars that are 600km apart are moving towards each other. Their speeds differ by 6km per hour and the cars are 123km apart af

ter 4.5 hours. Find the speed of each car
Mathematics
1 answer:
Marina CMI [18]3 years ago
8 0

Answer: 56\ kmph,\quad 50\ kmph

Step-by-step explanation:

Given

Two cars are 600 km apart moving towards each other

Difference in their speed is 6 kmph

After 4.5 hr, they are 123 km apart that is, they covered a distance of 600-123=477\ km in 4.5 hours

Suppose their speeds is v_1\ \text{and}\ v_2

\therefore v_1-v_2=6\quad \ldots(i)

Also, distance traveled is given by

\Rightarrow 477=[v_1+v_2]4.5\\\Rightarrow v_1+v_2=106\quad \ldots(ii)

Solve, (i) and (ii) , we get v_1=56\ kmph\ \text{and}\ v_2=50\ kmph

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Andrew [12]
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5 0
3 years ago
Pls help with #14 and #15!!!Asap 15 points
inna [77]

Answer:

14. -g + 10, 15. 12k + 3

Step-by-step explanation:

I'm assuming you want to simplify the equation. For 14, we distribute -2. This gets us -2g + 10 + g. We can simplify that to -g + 10. We can't simplify that, so our answer is complete. For 15, we combine 8k and 4k to get 12k + 3. That can't be simplified, so we are done.

8 0
3 years ago
Sherri saves nickels and dimes in a coin purse for her daughter. The total value of the coins in the purse is $0.95. The number
forsale [732]
I’m guessing that this is for systems of equations?
n - nickels
d - dimes

These are the equations you start off with.
n = 5d-2
0.95 = 0.10d+0.05n

Substitute the top equation for n into the variable n in the bottom equation.
0.95 = 0.10d+0.05(5d-2)

Solve for d.
0.95 = 0.10d+0.25d-0.10
1.05 = 0.35d
3 = d

Substitute d into the top equation and solve for n.
n = 5(3)-2
n = 15-3
n = 12

There are 3 dimes and 12 nickels in the coin purse! Hope this helped <3

7 0
3 years ago
Read 2 more answers
In a research laboratory, a scientist measures the mass of a 1-carat diamond and finds it to be 200 milligrams, measured to the
vlada-n [284]

Answer:

D=3.5\ gr/cm^3

Step-by-step explanation:

<u>Density</u>

The density of an object of mass m and volume V is given by

\displaystyle D=\frac{m}{V}

It can be expressed in common units like gr/lt, Kg/m^3, gr/cm^3 or any other combination of proper mass [M] by volume [V] units.

The data provided in the question is

m=200\ mg = 0.2\ gr

V=0.057\ cm^3

Thus, the measured density is

\displaystyle D=\frac{0.2\ gr}{0.057 \ cm^3}

\boxed{D=3.5\ gr/cm^3}

We have expressed the result with 1 decimal place because the mass was measured to the nearest hundred milligrams (or one-tenth grams). Any further decimal is senseless because that precision comes from calculations, not from measurements.

6 0
3 years ago
What is x equal to =
a_sh-v [17]

Answer:

Step-by-step explanation:

X= 3\frac{1}{3} or\frac{10}{3}

5 0
3 years ago
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