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lianna [129]
3 years ago
6

Two cars that are 600km apart are moving towards each other. Their speeds differ by 6km per hour and the cars are 123km apart af

ter 4.5 hours. Find the speed of each car
Mathematics
1 answer:
Marina CMI [18]3 years ago
8 0

Answer: 56\ kmph,\quad 50\ kmph

Step-by-step explanation:

Given

Two cars are 600 km apart moving towards each other

Difference in their speed is 6 kmph

After 4.5 hr, they are 123 km apart that is, they covered a distance of 600-123=477\ km in 4.5 hours

Suppose their speeds is v_1\ \text{and}\ v_2

\therefore v_1-v_2=6\quad \ldots(i)

Also, distance traveled is given by

\Rightarrow 477=[v_1+v_2]4.5\\\Rightarrow v_1+v_2=106\quad \ldots(ii)

Solve, (i) and (ii) , we get v_1=56\ kmph\ \text{and}\ v_2=50\ kmph

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What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?
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Answer:

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

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Step-by-step explanation:

Given:  

Let,  

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To Find:  

Equation of Line  that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?  

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x-6y=42    ..................Given

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So,

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m\times m_{1}=-1\\Substituting\ m\\ \dfrac{1}{6} m_{1}=-1\\\\m_{1}=-6

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,  

i.e equation in point - slope form

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Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get

(y-7)=-6(x--2)=-6(x+2)=-6x-12\\\\\therefore 6x+y=-5.......is\ the required\ equation\ of\ the\ line

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

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