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GalinKa [24]
3 years ago
13

In circle M, diameters JL and HK each measure 16 centimeters.

Mathematics
1 answer:
sashaice [31]3 years ago
7 0

Answer:

3.5 cm

Step-by-step explanation:

Length of an arc is a "part" of the circumference of a circle.

The circumference is the perimeter of the circle. Formula is:

C=\pi d

Where

C is circumference

d is diameter

Given diameter is 16, the circumference would be:

C=\pi (16)\\C=16\pi\\C=50.27

Now, the arc is 25 degrees, which is 25/360 th of the circle's circumference [recall, there is 360 degrees in whole circle].

So, we multiply the circumference we got by (25/360) to get our answer:

\frac{25}{360}*50.27=3.5

Minor Arc JH = 3.5 cm

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Which function represents g(x), a reflection of f(x) = 6(one-third) Superscript x across the y-axis?
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The function g(x)=6(3)^{x} represents a reflection of f(x)=6(\frac{1}{3})^{x} across the y-axis ⇒ 3rd answer

Step-by-step explanation:

Let us revise the reflection across the axes

  • If the function f(x) reflected across the x-axis, then its image is g(x) = - f(x)
  • If the function f(x) reflected across the y-axis, then its image is g(x) = f(-x)

∵ f(x)=6(\frac{1}{3})^{x}

∵ g(x) is the image of f(x) after reflection across the y-axis

- From the rule above reflection across the y-axis changes the sign of x

∴ g(x)=6(\frac{1}{3})^{-x}

∵ (a)^{-n}=(\frac{1}{a})^{n}

∵ (\frac{1}{a})^{-n}=(a)^{n}

∴ (\frac{1}{3})^{-x}=(3)^{x}

∴ g(x)=6(3)^{x}

The function g(x)=6(3)^{x} represents a reflection of f(x)=6(\frac{1}{3})^{x} across the y-axis

Learn more:

You can learn more about reflection in brainly.com/question/5017530

#LearnwithBrainly

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3 years ago
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Answer:

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Step-by-step explanation:

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I just need the answer bru why’s it gotta Make write 20 words‍♂️ this is dumb as hell bru‍♂️
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Answer:

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Step-by-step explanation:

W^7/W^-2=W^7+2=W^9 ( when divide subtract the exponent (7-(-2))

W^?/W² = W^?-2

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Answer:

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Step-by-step explanation:

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.5 or .50 is the answer
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