Let A represent the speed of car A. Using your formula,
.. A*2 = D
.. (A +15)*1.5 = D . . . . . the same distance in a shorter time at a higher speed
Equating the two expressions for D, we get
.. 2A = 1.5(A +15)
.. 2A = 1.5A +22.5 . . . . . eliminate parentheses
.. 0.5A = 22.5 . . . . . . . . .subtract 1.5A
.. A = 22.5/0.5 = 45 . . . .divide by 0.5
Car B was 15 mph faster than this.
Car B traveled at 60 miles per hour.
Answer:
16s^2 -9
Step-by-step explanation:
(4s+3)(4s–3)
FOIL
first : 4x*4x = 16s^2
outer -3 *4s = -12s
inner 3*4s = 12s
last = 3* -3 = -9
Add them together
16s^2 -12s+12s -9
Combine like terms
16s^2 -9
Answer:
y=10
Step-by-step explanation:
you first add 10 to both sides
the bring down the -5y
thr divide it -50 with -5
Answer:
D
Step-by-step explanation:
