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CaHeK987 [17]
3 years ago
14

Ms. Clayton took a survey of the students in her classes to see how many are likely to attend the school dance. She surveyed 48

students, and twelve said they would attend. If the school has 640 students, how many students might Ms. Clayton expect to attend the school dance?
Mathematics
1 answer:
Masteriza [31]3 years ago
4 0
I believe it would be 160 because if you divide the number of students they surveyed by the amount that said they would attend (48/12) you get 4 then if you divide 4 by the amount of students in total (640/4) you get 160
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3/4 divides by 5

3/4 x 1/5 = 3/20 of a gallon
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Plz help i will mark brainlist
iragen [17]
Y=x+4
3x+Y=-8

3x+x+4=-8
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Y=-3+4
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6 0
2 years ago
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A function is graphed on a coordinate grid. As the domain values approach infinity, the range values approach infinity. As the d
Sloan [31]

Answer:

D) Quadratic

Step-by-step explanation:

A function is graphed on a coordinate grid.

  • As the domain values approach infinity, the range values approach infinity.

       Domain: If x\rightarrow \infty then

       Range: y\rightarrow \infty

  • As the domain values negative infinity, the range values approach infinity.

       Domain: If x\rightarrow -\infty then

       Range: y\rightarrow \infty

We need to choose correct option which follows given domain and range.

Only quadratic function will follow the rule because it has even degree polynomial.

Quadratic function: f(x)=ax^2+bx+c

Degree = 2 and leading coefficient is positive.

Domain: x\belong (-\infty,\infty)

Range: y\belong (b,\infty)

Hence, D is correct option.

4 0
3 years ago
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Which is f(6) for the quadratic function graphed?<br> 0 -2<br> * -0.5<br> 1.5<br> 4
rusak2 [61]

Answer:

4

Step-by-step explanation:

I'm pretty sure theres a graph to this so....

The given parabolic graph of quadratic function

To find:What is F(6) for the quadratic function

Solution:We have given graph of quadratic function

there is a different value for Y and a different value for X

For f(6)

here X=6, need to find graph of quadratic function

X=6

f(6)=4

Y=4

Your welcome :)

4 0
2 years ago
PLEASE HELP ME I BEG I WILL GIVE BRAINLIEST
ohaa [14]

Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

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