All categories

3 years ago

What is 6x multiplied by x

Mathematics

2 answers:

Lerok [7]3 years ago

5 0

6 multiply by x

= 6 * x * x

= 6*x^2

= 6x^2

I hope that's help !

n200080 [17]3 years ago

4 0

Since the variable x has an invisible one next to it, which is 1x, it is 6x.

You might be interested in

What is the gcf of 25, 35 and 45

nekit [7.7K]

GCF of 25, 35 and 45 is 5

Step-by-step explanation:

The greatest factor that divides all given numbers is called the greatest common factor.

In case of 25, 35 and 45, the greatest number that will divide all three will be the GCF

For that, we have to find the factors of all numbers

$25 = 1,5,5\\35 = 1,5,7\\45 = 1,3,5,9$

By observing the factors we can say that the greatest common factor is 5

Hence,

GCF of 25, 35 and 45 is 5

Keywords: GCF, Factors

Learn more about GCF at:

#LearnwithBrainly

4 0

3 years ago

Match the parametric equations with the verbal descriptions of the surfaces by putting the letter of the verbal description to t

alukav5142 [94]

Answer:

1. B

2. C

3. A

4. D

Step-by-step explanation:

The parametric equations of the circular cylinder are:

$x(u,v)=a\cos v\\y(u,v)=a\sin v\\z(u,v)=u$

If the orientation of the cylinder is changed to have the height $u$ along the x-axis, the parametric equations of the cylinder match:

$3. \mathbf{r} \left( u, v \right) = u \mathbf{i} + \cos v \mathbf{j} + \sin v \mathbf{k}$

The parametric equations of the circular paraboloid are:

$x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=u^2$

Using the units vectors the parametric equations match:

$1. \mathbf{r} \left( u, v \right) = u \cos v \mathbf{i} + u \sin v \mathbf{j} + u^{2} \mathbf{k}$

The parametric equations of the cone are:

$x(u,v)=au\cos v\\y(u,v)=au\sin v\\z(u,v)=u$

Using the units vectors and rotating the base of the cone from $z=0$ to $x=0$ the parametric equations match:

$2. \mathbf{r} \left( u, v \right) = u \mathbf{i} + u \cos v \mathbf{j} + u \sin v \mathbf{k}$

The equation left is the equation of a plane:

$4. \mathbf{r} \left( u, v \right) = u \mathbf{i} + v \mathbf{j} + \left( 2u - 3v \right) \mathbf{k}$

5 0

3 years ago

A ball dropped from the top of a building can be modeled by the function f(t)=-16^2+36, where t represents time in seconds

Viefleur [7K]

Answer:

The ball is dropped from a height of 36 feet

The bee and the ball will collide after approximately 1.3 seconds

The bee and the ball will collide at approximately 8 feet above the ground

The ball hits the ground after 1.5 seconds

Step-by-step explanation:

The complete question is

A ball dropped from the top of the building can be modeled by the function f(t)=-16t^2 + 36 , where t represents time in seconds after the ball was dropped. A bee's flight can be modeled by the function, g(t)=3t+4, where t represents time in seconds after the bee starts the flight.

The graph represents the situation.

select all that apply

1) The bee launches into flight from the ground.

2) The ball is dropped from a height of 36 feet.

3) The bee and the ball will collide after approximately 1.3 seconds.

4) The bee and the ball will collide after approximately 8 seconds.

5) The bee and the ball will collide at approximately 8 feet above the ground.

6) The bee and the ball will not collide.

7) The ball hits the ground after 1.5 seconds

see the attached figure to better understand the problem

Verify all the options

case 1) The bee launches into flight from the ground.

The statement is false

Because

we have

$g(t)=3t+4$

For t=0

$g(t)=3(0)+4=4\ ft$

That means ----> The bee launches into flight from a height 4 feet above the ground

case 2) The ball is dropped from a height of 36 feet

The statement is true

Because

For t=0

$f(t)=-16(0)^2+36=36\ ft$

case 3) The bee and the ball will collide after approximately 1.3 seconds

The statement is true

Because

Equate f(t) and g(t)

$-16t^2+36=3t+4$

$-16t^2-3t+32=0$

solve the quadratic equation by graphing

The solution is t=1.324 sec

see the attached figure N 2

case 4) The bee and the ball will collide after approximately 8 seconds

The statement is false

Because, the bee and the ball will collide after approximately 1.3 seconds (see case 3)

case 5) The bee and the ball will collide at approximately 8 feet above the ground

The statement is true

Because

For t=1.324 sec

substitute the value of t in f(t) or g(t)

$g(t)=3(1.324)+4=7.97\ ft$

case 6) The bee and the ball will not collide

The statement is false

see case 3) and case 5)

case 7) The ball hits the ground after 1.5 seconds

The statement is true

Because

we know that

The ball hit the ground when the value of f(t) is equal to zero

For f(t)=0

$-16t^2+36=0$

$t^2=\frac{36}{16}$

$t=\frac{6}{4}=1.5\ sec$

4 0

3 years ago

Read 2 more answers

Sooooo bored ask me anything even if it´s not on the list

serg [7]

Answer:

What oets do you like? whats your height u noob

Step-by-step explanation:

6 0

3 years ago

What is the slope of line a?

marta [7]

Answer:

-1/3

Step-by-step explanation:

Slope is defined as "rise over run". If you count out the units, you should be able to see that your rise is 1 and your run is 3 and is pointing downward, so your answer is -1/3.

Alternatively you could use Slope Formula: $m = \frac{y2-y1}{x2-x1}$

8 0

3 years ago

Read 2 more answers