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3 years ago

What is 6x multiplied by x

Mathematics

2 answers:

Lerok [7]3 years ago

5 0

6 multiply by x

= 6 * x * x

= 6*x^2

= 6x^2

I hope that's help !

n200080 [17]3 years ago

4 0

Since the variable x has an invisible one next to it, which is 1x, it is 6x.

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In the figare, Linet Intersects parallel Lines m and n.

otez555 [7]

Answer:

Step-by-step explanation:

<2 and <3 are vertically opposite angles and are also congruent. Both the angles are hence called vertical angles.

5 0

3 years ago

Find n. 8/12 = n/48. n = ?

Novosadov [1.4K]

Answer:

n = 32

Step-by-step explanation:

Given:

$\frac{8}{12}=\frac{n}{48}$

Solve:

$\mathrm{Cross\; Multiply:}$

$\frac{8}{12}=\frac{n}{48}$

$\mathrm{48\times8=384}$

$\mathrm{384\div12=32}$

$\mathrm{Hence,n=32}$

~ $\mathrm{[Kavinsky]}$

7 0

2 years ago

Read 2 more answers

What are the possible values of x if (4x - 5)2 = 49? Check all that apply. uw we we

kogti [31]

Answer:

x = - $\frac{1}{2}$ , x = 3

Step-by-step explanation:

Given

(4x - 5)² = 49 ( take the square root of both sides )

4x - 5 = ± $\sqrt{49}$ = ± 7 ( add 5 to both sides )

4x = 5 ± 7, thus

4x = 5 - 7 = - 2 ( divide both sides by 4 )

x = $\frac{-2}{4}$ = - $\frac{1}{2}$

4x = 5 + 7 = 12 ( divide both sides by 4 )

x = 3

As a check

Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.

x = - $\frac{1}{2}$

left side = (- 2 - 5)² = (- 7)² = 49 = right side ⇒ solution

x = 3

left side = (12 - 5)² = 7² = 49 = right side ⇒ solution

7 0

3 years ago

A projectile is fired with muzzle speed 250 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe

qaws [65]

The projectile's horizontal and vertical positions at time $t$ are given by

$x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ\,t$

$y=30\,\mathrm m+\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ\,t-\dfrac g2t^2$

where $g=9.8\dfrac{\rm m}{\mathrm s^2}$ . Solve $y=0$ for the time $t$ it takes for the projectile to reach the ground:

$30+\dfrac{250}{\sqrt2}t-4.9t^2=0\implies t\approx36.2458\,\mathrm s$

In this time, the projectile will have traveled horizontally a distance of

$x=\dfrac{250\frac{\rm m}{\rm s}}{\sqrt2}(36.2458\,\mathrm s)\approx6400\,\mathrm m$

The projectile's horizontal and vertical velocities are given by

$v_x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ$

$v_y=\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ-gt$

At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about $\sqrt{176.77^2+(-178.43)^2}\dfrac{\rm m}{\rm s}\approx250\dfrac{\rm m}{\rm s}$ .

7 0

3 years ago

Find the area of the shaded region.

densk [106]

[1]

A1 = (h (a + b)) / 2

A1 = (21 (17 + 32)) / 2

A1 = (21 x 49) / 2

A1 = 1,029 / 2

A1 = 514.5 mm²

[2]

A2 = (b x h) / 2

A2 = (11 x 9) / 2

A2 = 99 / 2

A2 = 49.5 mm²

[3]

The area of the shaded region =

A1 - A2 =

514.5 mm² - 49.5 mm² =

465 mm²

The answer is 465 mm².

4 0

3 years ago