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Gnom [1K]
3 years ago
15

Rectangle PQRS is rotated 90 counterclockwise about the origin what are the coordinates of point Q

Mathematics
2 answers:
inna [77]3 years ago
5 0
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.

When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)

Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)

point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)

point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)

Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)

Hope this helps :)
den301095 [7]3 years ago
4 0

Answer:

Please give us more information. An image might help. If you do this, I will answer in the comments section.

Step-by-step explanation: Go back to your math, copy the image, then go back to Brainly, and paste it in.

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Sedbober [7]

Step-by-step explanation:

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that's how you find the answer.

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6 0
3 years ago
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A class is selling magazines as a fundraiser. Of the 200 magazines sold, Ananda sold 1/8 of them. Gina sold 0.065 of the magazin
Zina [86]
To figure out which sold the most magazines, multiply each number by 200 to find the answer. Let's start with 1/8. 200 * 1/8 = 25. Then 0.065 * 200 = 13.

3/100 * 200 = 6

200 * 0.105 = 21.

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3 years ago
Seorang pemilik toko sepatu ingin mengisi tokonya dengan sepatu laki-laki paling sedikit 100 pasang dan sepatu wanita paling sed
taurus [48]

Answer:

<em>The biggest profit that can be obtained by the shop owner= </em>IDR 2,750,000.

Step-by-step explanation:

We need to form a LPP( Linear Programming Problem) for the following problem and solve it to get the maximize the profit.

Let x denote the number of men's shoe and y denote the number of female shoes.

Maximize z= 10000x+5000y----------(1)

             x≥100 ( since a shoe store owner wants to fill his shop with at least    100 pairs of men's shoes )

            y≥150  (at least 150 pairs of women's shoes).

also x+y≤400   (The store can only accommodate 400 pairs of shoes).

         x≤150    (male shoes should not exceed 150 pairs).

⇒         100≤x≤150

Hence the optimal solution of an LPP always lie on the end points.

We have end points as:

(100,300), (150,250), (100,150),(150,150).

by putting these value in equation (1) we see which give the maximum solution.

for (100,300) i.e. x=100 and y=300:   z=2,500,000

for (150,250) i.e. x=150 and y=250:  z=2,750,000

for (100,150) i.e. x=100 and y=150: z=1,750,000

for (150,150) i.e. x=150 and y=150: z=2,250,000

Hence maximum profit is obtained at x=100 and y=300.

i.e. to maximize the profit:

<em>Number of men's shoes to be kept in store=100</em>

<em>and number of women's shoes to be kept in store=300</em>

<em>The biggest profit that can be obtained by the shop owner= </em>IDR 2,750,000.

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oee [108]

Answer:

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3 years ago
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Answer:

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Step-by-step explanation:

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