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dimulka [17.4K]
3 years ago
15

May someone see if I got this Math problem correct, Thank you.

Mathematics
1 answer:
TEA [102]3 years ago
5 0
I think you are right !!!!! I am also little bit confused!
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Which expression is equivalent to the given expression? Assume the denominator does not equal zero, OA 4 7y? Oc. Try OD 22 23​
zhenek [66]

Answer:

answer is A) 2y⁴/x⁴

:-))

5 0
3 years ago
Simplify each expression. 1-4b+3b+11
meriva
The correct answer is -b+12
5 0
3 years ago
Read 2 more answers
When Colton commutes to work the amount of time it takes him to arrive is normally distributed with a mean of 41 minutes and a s
larisa86 [58]

Answer:

The Probability that commute will be between 33 and 35 minutes to the nearest tenth =  0.0189 ≅1.89%  

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

<em>Given mean of the Population(μ) = 41 minutes</em>

<em>Given standard deviation of the Population (σ) =  3 minutes</em>

<em>let  'X' be the random variable of Normal distribution</em>

Let X = 33

Z = \frac{x -mean}{S.D} =\frac{33-41}{3} = -2.66

let X = 35

Z = \frac{x -mean}{S.D} =\frac{35-41}{3} = -2

<u><em>Step(ii)</em></u>:-

The Probability that commute will be between 33 and 35 minutes to the nearest tenth

P(33≤ X≤35) = P(-2.66 ≤X≤-2)

                     = P( X≤-2) - P(X≤-2.66)

                     =  0.5 - A(-2) - (0.5 - A(-2.66)

                     =   0.5 -0.4772 - (0.5 -0.4961)  (From normal table)

                    = 0.5 -0.4772 - 0.5 +0.4961

                     = 0.4961 - 0.4772

                    = 0.0189

<em>The Probability that commute will be between 33 and 35 minutes to the nearest tenth =  0.0189 ≅1.89%                 </em>  

                     

4 0
4 years ago
What is the equation in vertex
jok3333 [9.3K]

\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{ope ns~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \stackrel{\textit{vertex}}{(3,-2)}~~ \begin{cases} h = 3\\ k = -2 \end{cases}\implies y=a(x-3)^2-2 \\\\\\ \stackrel{\textit{passes through}}{(5,-1)}~~ \begin{cases} x=5\\ y= -1 \end{cases}\implies -1=a(5-3)^2-2\implies 1=a(2)^2 \\\\\\ 1=4a\implies \cfrac{1}{4}=a~\hfill \boxed{y=\cfrac{1}{4}(x-3)^2-2}

5 0
3 years ago
Read 2 more answers
5x + 6y = 20 , 8x - 6y = -46
serg [7]

Answer:

5x + 6y = 20_____(1)

8x - 6y = -46_____(2)

Solving simultaneously:

Eqn(1) + Eqn(2)

5x + 8x + 6y + (-6y) = 20 + (-46)

13x = -26

x = -2

substituting this into Eqn (1):

5(-2) + 6y = 20

-10 + 6y = 20

6y = 30

y = 5

hence:

x = -2,y = 5.

7 0
3 years ago
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