May someone see if I got this Math problem correct, Thank you.
1 answer:
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Answer:
The Probability that commute will be between 33 and 35 minutes to the nearest tenth = 0.0189 ≅1.89%
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
<em>Given mean of the Population(μ) = 41 minutes</em>
<em>Given standard deviation of the Population (σ) = 3 minutes</em>
<em>let 'X' be the random variable of Normal distribution</em>
Let X = 33
let X = 35
<u><em>Step(ii)</em></u>:-
The Probability that commute will be between 33 and 35 minutes to the nearest tenth
P(33≤ X≤35) = P(-2.66 ≤X≤-2)
= P( X≤-2) - P(X≤-2.66)
= 0.5 - A(-2) - (0.5 - A(-2.66)
= 0.5 -0.4772 - (0.5 -0.4961) (From normal table)
= 0.5 -0.4772 - 0.5 +0.4961
= 0.4961 - 0.4772
= 0.0189
<em>The Probability that commute will be between 33 and 35 minutes to the nearest tenth = 0.0189 ≅1.89% </em>