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Morgarella [4.7K]
3 years ago
8

Simplify each expression. 1-4b+3b+11

Mathematics
2 answers:
meriva3 years ago
5 0
The correct answer is -b+12
Simora [160]3 years ago
5 0

Answer:

1-4b + 3b+11

1-11+4b+3b

-10+6b

-16

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PLEASE HELP I WILL GIVE BRAINLIEST TO THE FIRST PERSON TO ANSWER
jekas [21]

Answer:

1. 2x = 60

x = 30

y = x - 5 = 30 - 5 = 25

2. x= 11

4 0
3 years ago
Find the product (4x-5y)^2
sleet_krkn [62]
To find the product of (4x-5y)^2,
we can rewrite the problem as:
(4x-5y)(4x-5y) (two times because it is squared)

Now, time to use that old method we learned in middle school:
FOIL. (Firsts, Outers, Inners, and Lasts)

FOIL can help us greatly in this scenario.
Let's start by multiplying the 'Firsts' together:
4x * 4x = <em>16x^2</em>

Now, lets to the 'Outers':
4x * -5y = <em>-20xy</em> 

Next, we can multiply the 'Inners':
-5y * 4x = <em>-20xy</em>

Finally, let's do the 'Lasts':
-5y * -5y = <em>25y</em>^2

Now, we can take the products of these equations from FOIL and combine like terms. We have: 16x^2, -20xy, -20xy, and 25y^2.
-20xy and -20xy make -40xy.

The final equation (product of (4x-5y)^2) is:
16x^2 - 40xy + 25y^2

Hope I helped! If any of my math is wrong, please report and let me know!
Have a good one.
4 0
3 years ago
Simplify the expression:<br> ( X + 5)( X-7)
Hitman42 [59]
(x + 5)(x - 7)
x(x - 7) + 5(x - 7)
x(x) - x(7) + 5(x) - 5(7)
x² - 7x + 5x - 35
x² - 2x - 35
7 0
3 years ago
Read 2 more answers
Consider the problem 208.4 x 396.51. If I round 208.4 down to the nearest hundreds place and I round 396.51 up to the nearest hu
WARRIOR [948]

Answer:

The answer is 82,472

Step-by-step explanation:

The nearest estimate of 208.4=208.

The nearest estimate of 396.51 is 396.5

So the product is 82,472

6 0
2 years ago
Use the principle of inclusion and exclusion to find the number of positive integers less than 1,000,000 that are not divisable
wel
This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.

∴N(c₁) = \frac{999,999}{6} = 166666
N(c₂) = \frac{999,999}{4} = 250000
∴N(c₁c₂) = \frac{999,999}{24} = 41667
∴ Number of positive integers that are not divisible by 4 or 6,

N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4
8 0
3 years ago
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