Question

(HELP NEEDED ASAP) A line that includes the point (16,1) has a slope of 1/16. what is it’s equation in slope-intercept form? write your answer using integers, proper fractions, and improper fractions in simplest form.

Answer 1

Answer:

y = (1/16)x

Step-by-step explanation:

y = (1/16)x + c

1 = (1/16)(16) + c

c = 1 - 1

c = 0

y = (1/16)x

Answer 2

Answer:

y = x/16 - 0

Step-by-step explanation:

Using a point slope form equation

y - y1 = m(x - x1)

Given

( 16 , 1)

Slope = 1/16

x1 = 16

y1 = 1

Insert the values

y - y1 = m(x - x1)

y - 1 = 1/16( x - 16)

Using a slope intercept form equation

y = mx + c

Open the bracket

y - 1 = 1/16(x - 16)

y - 1 = (x - 16)/16

y = (x - 16)/16 + 1

LCM = 16

y = (x - 16 + 16)/16

y = (x - 0)/16

Following the slope intercept form equation

y = x/16 - 0/16

y = x/16 - 0

The equation is y = x/16 - 0