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DENIUS [597]
2 years ago
9

Comment prouver par Raisonnement par équivalences successives que

Mathematics
1 answer:
kicyunya [14]2 years ago
3 0

Answer:

Que tambien

Step-by-step explanation:

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Please help me need ASAP
Ket [755]

Answer:

preety sure its answer 3

Step-by-step explanation:

4 0
2 years ago
Misha and Dontavious were asked to solve the following problem using linear programming. A local school district can operate a l
bearhunter [10]

Answer:

did you get the answer?

Step-by-step explanation:

4 0
3 years ago
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What is the length of the focal width x=-1/8y^2
Levart [38]
The standard equation is 4p(x-h) = (y-k)^2 where |p| = focal distance |4p| = focal width.

<span>x=-1/8y^2
-8x=y^2
4*(-2)(x-0) =( y-0)^2

p = -2, h=0, k=0</span><span>

focal width = |4*(-2)| = 8

The answer to your question is that the length of the focal width is equal to 8.</span>
3 0
2 years ago
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Please Help!! A septic tank has the shape shown in the figure. How many gallons does it hold? (1 cu ft = 7.48 gallons.) (Round t
Hoochie [10]

The overall volume is the sum of the volume of a cylinder of height 5'9" and diameter 3'6", and a sphere of diameter 3'6" (two hemispheres = full sphere).

Volume of the cylinder = (area of the base) x (height) = pi * (diameter/2)^2 * 5.75ft = 3.1415 * (3.5ft/2)^2 * 5.75 ft = 55.32 ft^3

Volume of the sphere = 4/3 * pi * (3.5ft)^3 / 8 = 22.45 ft^3

Total volume = (Volume of cylinder) + (Volume of sphere) = (55.32 + 22.45) ft^3 = 77.77 ft^3

3 0
3 years ago
A circular pond 24 yd in
Schach [20]

Answer:

The walk will cost $8164.

Step-by-step explanation:

Given:

Diameter of the circular pond (D) = 24 yd

Width of the gravel path (x) = 2 yd

Cost per yard of the path = $50

Now, radius of the circular pond is half of the diameter and is given as:

Radius,R=\frac{D}{2}=\frac{24}{2}=12\ yd

Now, area of the pond is given as:

A_{pond}=\pi R^2=3.14\times (12)^2=3.14\times 144=452.16\ yd^2

Area of the complete path including the pond area is given as:

A_{outer}=\pi(R+x)^2=3.14\times(12+2)^2=3.14\times196=615.44\ yd^2

Now, area of the gravel path can be obtained by subtracting the pond area from the total outer area. This gives,

A_{path}=A_{outer}-A_{pond}\\\\A_{path}=615.44-452.16=163.28\ yd^2

Now, using unitary method,

Cost of 1 square yard of path = $50

∴ Cost of 163.28 square yard of path = 50 × 163.28 = $8164

Hence, the walk will cost $8164.

5 0
3 years ago
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