Answer:
4.924 years
Step-by-step explanation:
Lets denote X the lifetime of a tv tube (In years). X has distribution 
, with 
unknown.
We know that P(X < 4) = 0.2. Using this data, we can find the value of throught standarization.
Lets call 
the standarization of X. Z has distribution N(0,1), and its cummulative function, 
is tabulated. The values of can be found in the attached file.
The value q such that 
doesnt appear on the table. We can find it by using the symmetry of the normal density function. The opposite of q, -q must verify that 
, hence -q must be equal to 0.84. Thus, q = -0.84
But this value of q should match with the number 
, so we have
Thus, the expected lifetime of TV tubes is 4.924 years.
I hope this works for you!
Answer:
yes, all of it is correct
Step-by-step explanation:
For the two triangles to be congruent, you would need the following angles and lengths to be congruent with each other.
Is there more to the question? Because it could be any hours..
Answer:
1. 28 − 3(x − 2) < 5x + 10 Given
2. 28 − (3)(x) + (-3)(-2) < 5x + 10 Distributive Property <em>a(b + c) = ab+ ac</em>
28 − 3x + 6 < 5x + 10
3. (28 + 6) - 3x < 5x + 10 Combine Like Terms
34 − 3x < 5x + 10
4. 34 - 3x + 3x < 5x + 3x + 10 Addition Property of Order
34 < 8x + 10
5. 34 - 10 < 8x + 10 - 10 Subtraction Property of Order
24 < 8x
6. 24/8 < 8x/8 Division Property of Order
3 < x
3dm, 18mm, 7cm, 1m...hope I helped!
