Number 2 is A and number 4 is c
Number 1 2 and 4 are the ones with 5
Surface area is the area of the faces added together.
First lets find the area of one of the triangles.
Area of triangle is 1/2*base*hight
Area=1/2*2*3= 3
Area of ONE tringle is 3, and area of the FOUR tringles is 4*3 whihc is 12
Now lets find area of square
area of square is side*side
So, area is 2*2 which is 4
Now lets add area of triangles+area of square
12+4 which 16
Surface area is 16
14-8=6 or 14-6=8 you're welcome
For the first term of 9x2, we know 3*3 is 9 and x*x is x2. For the middle term, we need two numbers that add to zero and cancel out the middle term, but that multiply to -16.
9x2 - 0x - 16
since the middle is 0, it is cancelled
9x2 - 16
(3x - 4)(3x + 4)
CHECK:
9x2 + 12x - 12x - 16
adding +12 and -12 cancels out
9x2 - 16
ANSWER: (3x - 4)(3x + 4)
Hope this helps! :)