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3 years ago

Okay so i have a question for yall!!!!!!!!!!11

Mathematics

1 answer:

Oduvanchick [21]3 years ago

4 0

I will, if i understand it!

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At a local department store, skirts typically cost $15. However, due to a special, the

Strike441 [17]

Answer: 20%

Step-by-step explanation:

(part / whole) * 100

(3 / 15) * 100 = 20%

4 0

3 years ago

Which ratio forms a proportion with 18/27

JulsSmile [24]

Answer:

$\frac{2}{3}$

Step-by-step explanation:

The given ratio is $\frac{18}{27}$

9 is the common factor of 18 and 27

divide numerator and denominator by 9

$\frac{18/9}{27/9} =\frac{2}{3}$

hence $\frac{2}{3}$ is proportion with $\frac{18}{27}$

6 0

3 years ago

A regular pentagonal prism has a volume of 2,850 cubic millimeters. what is the height of the prism? a regular pentagonal prism

zlopas [31]

Answer:

Height = 19mm.

Step-by-step explanation:

Area of a regular polygon = (A * P) / 2 where A = side / (2 * Tan (π / N)) where, N = Number of sides, A = Apothem, P = Perimeter.

Here A = 5, P = 5*12 = 60 so

Area of the base = (5 * 60) / 2 = 150 mm^2.

Volume = area base * height so

Height = volume / area of base

= 2850 / 150

= 19 mm.

5 0

2 years ago

Zack flips a coin a rolls a number cube with sides labeled 1 to 6. What is the probability that he gets heads and a number great

Nitella [24]

To get heads: 1/2 because there are two sides to a coin.

There are 6 sides on a cube and 2 numbers are greater than 4 (5 and 6) so 2/6

Now multiply: 1/2 * 2/6 = 2/12 = 1/6

1/6 is the final answer.

7 0

4 years ago

Read 2 more answers

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

5 0

3 years ago