Answer:
population standard deviation does not differ from 0.25
Step-by-step explanation:
The hypothesis :
σ² = 0.25²
σ² ≠ 0.25²
The Chisquare statistic, χ²: (n-1)*s²/σ²
Where s² = sample variance ; sample size, n = 30
Using calculator, the sample variance, s² = 0.1646
χ² = (n-1)*s²/σ²
χ²: (30 - 1) * 0.1646 / 0.25²
χ² = (29 * 0.1646) / 0.0625
χ² = 0.3292 / 0.0625
χ² = 5.2672
α = 0.05
Using the Pvalue from Chisquare calculator ; df = 29
Pvalue = 1
Since, Pvalue > α ; We fail to reject the null and conclude that population standard deviation does not differ from 0.25
Answer:
The length of river frontage for each lot are 96.55 ft. 98.85 ft, 101.15 ft and 103.45 ft.
Step-by-step explanation:
See the attached diagram.
The river frontage of 400 ft will be divided into 84 : 86 : 88 : 90 for each lot as AP, BQ, CR, DS and ET all are parallel.
Therefore, PQ : QR : RS : ST = 84 : 86 : 88 : 90 = 42 : 43 : 44 : 45
Let, PQ = 42x, QR = 43x, RS = 44x and ST = 45x
So, (42x + 43x + 44x + 45x) = 400
⇒ 175x = 400
⇒ x = 2.2988.
So, PQ = 42x = 96.55 ft.
QR = 43x = 98.85 ft.
RS = 44x = 101.15 ft and
ST = 45x = 103.45 ft
(Answer)
Answer:x = 56
Step-by-step explanation:
180-(60+64)=56
ANSWER
2
To find 1% of something (1/100 of something), divide by 100.
1% of 200 is 2.