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Pepsi [2]
3 years ago
15

XY bisects DF at point E. If DE=2y and EF=8y-3, find the value of DF​

Mathematics
1 answer:
nirvana33 [79]3 years ago
7 0

Answer:

Step-by-step explanation:

If XY bisects DF at point E, then DE = EF.

Given DE = 2y and EF = 8y-3

2y = 8y-3

subtract 8y from both sides

2y-8y = 8y-8y-3

-6y = -3

y = 3/6

y = 1/2

y = 0.5

DF = DE+EF

DF= 2y+8y-3

DF = 10y - 3

DF = 10(0.5)-3

DF = 5-3

DF = 2

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