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3 years ago

Hurry only have 20 min to complete

Mathematics

1 answer:

Bumek [7]3 years ago

8 0

Answer:

(5, 5 )

Explanation:

dilate means to get smaller so you divide 1/2 by (10,10)

half of 10 is 5, so the coordinate is (5, 5)

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Algebra

vladimir2022 [97]

(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1

-4x - 6y = -24
4x - 3y = 6

You can cancel out the x values by adding the two equations together.
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2

Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3

Check... (x = 3, y = 2)
2(3) + 3(2) = 12
6 + 6 = 12
12 = 12 <- this works!

4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!

5 0

3 years ago

Read 2 more answers

How do you write 6.0 as a percentage?

FrozenT [24]

Im pretty sure that it would be 600%. If it was 600% that would be 600 over 100 which would be 6

6 0

4 years ago

Complete the table to determine the amount of money that gabriella would recieve in exchange for 200 u.s dollars in each country

Anestetic [448]

Answer:

might wanna show us the table

3 0

3 years ago

Make R the subject<br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7BP%3D10%28Q-3R%29%7D%7BR%7D" id="TexFormula1" title=" \frac

Naddik [55]

I must assume that you meant the following:

10(Q-3R)

P = ----------------

Multiplying both sides by R, we get PR = 10R(Q-3R), or PR = 10RQ - 30R^2.

Rearranging these terms so that powers of R are in descending order:

30R^2 - 10RQ + PR = 0

Factoring out R, we get

R(30R - 10Q + P) = 0. This has two solutions:

R = 0, and 10Q - P

30R = 10Q - P, so that R = --------------

8 0

3 years ago

In the right triangle ?ABC, leg AC=6 cm and leg BC=8 cm. Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5. Find area of ?MN

Licemer1 [7]

Given : In Right triangle ABC, AC=6 cm, BC=8 cm.Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5.

To find : Area (ΔMNC)

Solution: In Δ ABC, right angled at C,

AC= 6 cm, BC= 8 cm

Using pythagoras theorem

AB² =AC²+ BC²

=6²+8²

= 36 + 64

→AB² =100

→AB² =10²

→AB =10

Also, AM:MN:NB=1:2.5:1.5

Then AM, MN, NB are k, 2.5 k, 1.5 k.

→2.5 k + k+1.5 k= 10

→ 5 k =10

Dividing both sides by 2, we get

→ k =2

MN=2.5×2=5 cm, NB=1.5×2=3 cm, AM=2 cm

As Δ ACB and ΔMNC are similar by SAS.

So when triangles are similar , their sides are proportional and ratio of their areas is equal to square of their corresponding sides.

$\frac{Ar(ACB)}{Ar(MNC)}=[\frac{10}{5}]^{2}$

$\frac{Ar(ACB)}{Ar(MNC)}=4$

But Area (ΔACB)=1/2×6×8= 24 cm²[ACB is a right angled triangle]

$\frac{24}{Ar(MNC)}=4$

→ Area(ΔMNC)=24÷4

→Area(ΔMNC)=6 cm²

4 0

3 years ago