X^2 + y^2 - 2x + 8y - 47 = 0
x^2 + y^2 - 2x + 8y = 47
(x^2 - 2x) + (y^2 + 8y) = 47
(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47
(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2
(x - 1)^2 + (y + 4)^2 = 64 = 8^2
r=8
Answer:
Inverse of exponential functions are logarithmic functions.
Step-by-step explanation:
Inverse functions exhibit a relationship where they undo each other mathematically. In this case, the inverse of an exponential function is a log function, where;
An exponential function y=a^x has its inverse as x=a^y
This exponential equation x=a^y is equivalent to the function y= logₐ x under the conditions; x=a^y : a>0 , a≠1
No I don't believe so, a proportional relation ship would be h= g x 3. So I believe it would be g3=h9 g6=h18 g9=h27. So that when you divide h by 3 it will always equal g. I hope this helped and wasn't too confusing.
Answer:
RT i think
Step-by-step explanation:
