Ask question

Ask question

All categories

3 years ago

6

A construction worker is making concrete by mixing sand, gravel, and cement in water. For each pound of sand, he uses 1 2/3 poun

ds of gravel. For each pound of gravel, he uses 2/5 pound of cement. He is making enough concrete that he needs to use 3 pounds of sand. How many pounds of cement does he use?
A. 1 pound
B. 1 4/15 pounds
C. 2 pounds
D. 2 1/15 pounds

1 answer:

guajiro [1.7K]3 years ago

5 0

Hi There!

Your answer should be B) 1 4/15 pounds

Hope this helps.

Good luck!

PLEASE MARK BRAINLIEST

- WeasuLL

You might be interested in

And 43 pls thank would help a lot

Furkat [3]

43. 125 milliliters

45. 9 tsp

49. 6 tsp

4 0

3 years ago

The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time

cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

$1\leq t\geq \sqrt{2}$

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

$h =20-5t^{2}$ -----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height $h = 15m$

Put height value in equation 1

$15 =20-5t^{2}$

$5t^{2} =20-15$

$5t^{2} =5$

$t^{2} =1$

$t =\pm1$

We know that the time is always positive, therefore $t=1$

when the stuntman is 10m above the ground.

height $h = 10m$

Put height value in equation 1

$10 =20-5t^{2}$

$5t^{2} =20-10$

$5t^{2} =10$

$t^{2} =\frac{10}{5}$

$t^{2} =2$

$t=\pm\sqrt{2}$

$t=\sqrt{2}$

Therefore ,time interval of camera film him is $1\leq t\geq \sqrt{2}$

7 0

3 years ago

13 ft<br> 8 ft<br> Jjjjjjjjjjjjj

Yuri [45]

Answer: if it is area 108ft2

Step-by-step explanation:

I'm sorry but I dont know what your question is.

6 0

3 years ago

Which of the following functions best describes this graph

Musya8 [376]

Answer:

D

Step-by-step explanation:

when x=2,6 then y=0

when y=12 then x=0

only applies for D

3 0

3 years ago

Find the value of x. Round your answer to the nearest tenth

Sati [7]

$x=13.8$

<u><em>Step-by-step explanation:</em></u>

Since the triangle is right use the tangent ratio to solve for x

$tan41^o=\frac{opposite}{adjacent}=\frac{12}{x}$

Multiply both sides by $x$

x × $tan41^o=12$ ( divide both sides by $tan41^o$ )

x = ≈ ( nearest tenth )

6 0

2 years ago