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Luden [163]
4 years ago
8

Contains the x intercept of 4x-y=8 and the point (-4,3)

Mathematics
2 answers:
nydimaria [60]4 years ago
7 0
<span>1.       </span><span>4x –y = 8, the point (-4, 3)
Let’s say y = 0
=> 4x – 8
=> 4x / 4 = 8 /4
=> x = 2
So the point is (2 , 0).
Now, we have 2 forms, the (2,0) and the (-4, 3)
=> (y2 – y1)(x2 – x1) = m
=> m = (0 - 3)(2-(-4))
=> m = (0 - 3)(2+4)
=>  m = (-3)(6)
=> m = -1/2
Thus,
y = -1/2x + a
=> 0 = -1 + a so a = 1
y = -x/2 + 1</span>



Anna35 [415]4 years ago
5 0

Answer:

4x –y = 8, the point (-4, 3)

Let’s say y = 0

=> 4x – 8

=> 4x / 4 = 8 /4

=> x = 2

So the point is (2 , 0).

Now, we have 2 forms, the (2,0) and the (-4, 3)

=> (y2 – y1)(x2 – x1) = m

=> m = (0 - 3)(2-(-4))

=> m = (0 - 3)(2+4)

=>  m = (-3)(6)

=> m = -1/2

Thus,

y = -1/2x + a

=> 0 = -1 + a so a = 1

y = -x/2 + 1

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Answer:

The value of  annuity is P_v  =  \$ 32058

Step-by-step explanation:

From the question we are told that

    The periodic payment is  P  =  \$ 1500

     The  interest rate  is   r =  8\%  =  0.08

     Frequency at which it occurs in a year is  n = 2 (semi-annually )

      The number of years is  t =  22 \ years

The  value of the annuity is mathematically represented as

             P_v  =  P *  [1  - (1 + \frac{r}{n} )^{-t * n} ] * [\frac{(1 + \frac{r}{n} )}{ \frac{r}{n} } ](reference EDUCBA website)

 substituting values

             P_v  =  1500 *  [1  - (1 + \frac{0.08}{2} )^{-22 * 2} ] * [\frac{(1 + \frac{0.08}{2} )}{ \frac{0.08}{2} } ]

             P_v  =  1500 *  [1  - (1.04 )^{-44} ] * [\frac{(1.04 )}{0.04} ]

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            P_v  =  \$ 32058

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7 0
3 years ago
A and B are centres of two circles of radii 8 cm and 1 cm such that AB =13 cm and angle ACB =90 degree where C is the centre of
Artyom0805 [142]

Answer:

50.28 sq. cm.

Step-by-step explanation:

A and B are centers of two circles of radii 8 cm and 1 cm such that AB =13 cm.

Now, angle ACB =90 degree where C is the center of another circle which touches the above two circles.

Now, ABC forms a right triangle where AB = 13 cm, AC = (r + 8) cm and BC = (1 + r) cm.

{Where r is the radius of the circle C.

Applying Pythagoras Theorem. AB² = AC² + BC²

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