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3 years ago

160 feet of lumber at $2.49 per foot

Mathematics

1 answer:

MissTica3 years ago

7 0

Answer:

$398.4

Step-by-step explanation:

160x$2.49=398.4

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marishachu [46]

Answer:

Step-by-step explanation:

the last number is the y intercept so the intercept in the line is -3.5 so I just matched them up.

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3 years ago

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Serggg [28]

Answer:

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Step-by-step explanation:

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2 years ago

Choose the slope and y-intercept that correspond with the graph. ignore this

krok68 [10]

Answer: The second choice is correct: slope is 3/4, y-intercept is 1

Step-by-step explanation: The y-intercept is where the line crosses the y-axis.

Look for places where the line intersects the grid at "cross-points" like (-4,-2) (0,1) and (4,4)

The slope is rise/run.

The difference in y-values is the rise. 4-1=3 1-(-2) is 3.

The rise is 3.

The difference in x-values is the run. 4-0=4 0-(-4) = 4

The run is 4

Rise/run = 3/4 That is the slope.

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3 years ago

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If you drove 60 miles in two hours, how many miles per hour did you drive?<br><br> 30 miles per hour

soldi70 [24.7K]

Answer:

30 mph

Step-by-step explanation:

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3 years ago

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An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n

kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 232 V

Sample mean, $\bar{x}$ = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 232\\H_A: \mu \neq 232$

We use Two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} }$ Putting all the values, we have

$t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971$

Since,

$|t_{stat}| > |t_{critical}|$

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

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3 years ago