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Arlecino [84]
3 years ago
14

Solve triangle pqr, given m A. R = 30° B. PR = 37.8 C. QR = 27.6 D. PQ = 53.6 Explain

Mathematics
1 answer:
Effectus [21]3 years ago
4 0
I believe that the answer should be  B.
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Which scenario could NOT be described by the following graph?
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D. the total distance a vehicle travels as it goes up a hill and then maintains a constant rate of speed at the top.

even if the distance increases the graph should rise up.

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Divide. write in smplest form 12÷2 2/7
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Find the value of x and then the measure of each angle. You should have 3 answers.
Softa [21]

Answer:

x = 7

3x + 11 = 32

8x + 2 = 58

Step-by-step explanation:

3x + 11 + 8x + 2 = 90

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A builder of houses needs to order some supplies that have a waiting time Y for delivery, with a continuous uniform distribution
xenn [34]

Answer:

The Expected cosy of the builder is $433.3

Step-by-step explanation:

$400 is the fixed cost due to delay.

Given Y ~ U(1,4).

Calculating the Variable Cost, V

V = $0 if Y≤ 2

V = 50(Y-2) if Y > 2

This can be summarised to

V = 50 max(0,Y)

Cost = 400 + 50 max(0, Y-2)

Expected Value is then calculated by;

Waiting day =2

Additional day = at least 1

Total = 3

E(max,{0, Y - 2}) = integral of Max {0, y - 2} * ⅓ Lower bound = 1; Upper bound = 4, (4,1)

Reducing the integration to lowest term

E(max,{0, Y - 2}) = integral of (y - 2) * ⅓ dy Lower bound = 2; Upper bound = 4 (4,2)

E(max,{0, Y - 2}) = integral of (y) * ⅓ dy Lower bound = 0; Upper bound = 2 (2,0)

Integrating, we have

y²/6 (2,0)

= (2²-0²)/6

= 4/6 = ⅔

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Cost = 400 + 50 * ⅔

Cost = 400 + 33.3

Cost = 433.3

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3 years ago
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