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KonstantinChe [14]
3 years ago
7

I need help finding the angle

Mathematics
1 answer:
geniusboy [140]3 years ago
5 0
180 - 115=
65 defenition ofsupplimentary angles
anlge mpn= 65
angle lpn=65 they are verticle angles
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How much candy can a human being fit in their mouth?
7nadin3 [17]
I don’t know but a better question is how many cavities do that human being want since they’re tryna see how much candy they can put in their mouth ? :)
8 0
3 years ago
If a regular polygon has exterior angles that measure 36 each, how many sides does the polygon have?
77julia77 [94]
To find this question's answer, we need to know that sum of the exterior angles of any given polygon is 360°. This is default and non-changeable.

Now we know that the sum of all exterior angles is 360°, the question says that one angle is equal to 36°.

When we divide them we get: \frac{360}{36} = 10

So, we found that there are 10 exterior angles.
6 0
3 years ago
Plz help ——————————————————————
Brilliant_brown [7]

Answer:

6.5

Step-by-step explanation

I think

7 0
3 years ago
Two chess players, A and B, are going to play 7 games. Each game has three possibleoutcomes: a win for A (which is a loss for B)
Lina20 [59]

Answer:

A) the possible outcomes for individual game is 210 games.

B) The possible outcome for this is 357 games.

C) Then the Possible Games are 267 games.

Step-by-step explanation:

A) Total number of individual games are 7 in which A ends up with 3 wins which give 4 remaining games. then there are two draw games from them. and in the end the remaining games are losses so,we useformula for combination:

                       (7C3)*(4C2)=210 \ games

B) Now Player A has 4 point that gives us 5 possibilities until we reach 7 games. Similarly B have 3 points which is same as player A gives us 5 possibilities until we reach 7 games. thus those two cases for player A and Player B can be stated as:

           (7C3)+(7C3)*(4C2)+(7C1)*(6C6)+(7C2)*(5C4)=357\  games

C) Lets say that player A ahs 4 points and player B has 3 points and all seven games have been played so.

c1) If player A has 4 wins and 3 losses then last win have to be in 7th match thus:the answer is (6C3).

c2) If player A has 3 win, 2 draws and 3 losses thus it means that final match cannot be a loss thus the answer is (6C2)*(5C3).

c3) Now lastly if player A has 1 win and 5 draws we can arrange them arbitrarily thus the answer here is (7C1).

c4) now If player A has 2 wins, 4 draws and 2 losses thus answer is (6C1)*(6C2)

Sum of all the cases is

               (6C3)+(6C2)*(5C3)+(7C1)+(6C1)*(6C2)=267\ games

4 0
3 years ago
Mr Lowry paid $32 for 5 boxes of crayons. How many dollars per box?
butalik [34]

Answer:

6 dollars and 40 cents

Step-by-step explanation:

To get the answer, you would do 32/5 which equals 6.4, which is the same as saying 6 dollars and 40 cents.

5 0
2 years ago
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