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4 years ago

20 POINTS ANSWER QUICK PLEASE!! SHOW ALL WORK

Mathematics

1 answer:

katen-ka-za [31]4 years ago

4 0

5x+8=4(3x+9) 5x+8=12x+36. 5x=12x+28

-7x=28. Divide both sides by -7 so x=-4

4y+8=4(2y-5). 4y+8=8y-20. 4y=8y-28

-4y=-28. Divide both sides by -4 so y=7

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What is the answer to number nine also how do I solve for it? Thanks:)

Tanya [424]

Well the whole ratio is 14 sooooo
98 ÷ 14 =7

for food tents it would be 9 x 7 which is 63

And for retail tents 5 x 7which is 35

so the whole ratio is 63: 35

7 0

3 years ago

I need some help plz...

SIZIF [17.4K]

the answer is y>-2x+4

5 0

4 years ago

Arrange these numbers in order from least to greatest <br><br> 1/2, 0,-2,1

Andru [333]

Answer:

-2, 0, 1/2, 1

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Evaluate each expression

qwelly [4]

Step-by-step explanation:

a = 2
b = 3
c = 5

$\longrightarrow \rm{{\Bigg ( \dfrac{a}{b} \Bigg )}^c} \\ \\ \longrightarrow \rm{{\Bigg ( \dfrac{2}{3} \Bigg )}^5} \\ \\ \qquad \qquad \bigstar \: \boxed{ \bf{ \Bigg ({\frac{x}{y} \Bigg )}^{m} = \frac{ {x}^{m} }{ {y}^{m}} }} \\ \\ \longrightarrow \rm{ \frac{ {(2)}^{5} }{ {(3)}^{5} } } \\ \\ \longrightarrow \bf{ \frac{ 32 }{ 243} }$

Therefore, 32/243 is the answer.

3 0

3 years ago

(t-distribution) A manufacturing firm claims that the batteries used in laptop computers will last an average of 50 months. To m

statuscvo [17]

Answer:

There is an 38.21% probability that we find this lifespan for our sample average, or something even shorter.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A manufacturing firm claims that the batteries used in laptop computers will last an average of 50 months. This means that $\mu = 50$ .

We found that the sample had a average lifespan of 47.3 months, and a standard deviation of s = 9 months. What is the probability that we find this lifespan for our sample average, or something even shorter?

We have to find the pvalue of Z when $X = 47.3$ .

We are working with a sample mean, so we use the standard deviation of the sample in the place of $\sigma$ . That is $s = 9$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{47.3-50}{9}$

$Z = -0.3$

$Z = -0.3$ has a pvalue of 0.3821.

There is an 38.21% probability that we find this lifespan for our sample average, or something even shorter.

7 0

3 years ago