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QveST [7]
3 years ago
11

Consider the polynomial P(x)=x³+kx²+x+6.Find the value of k so that x+1 is a factor of P.

Mathematics
1 answer:
sergiy2304 [10]3 years ago
4 0

Answer:

The value of k will be -4      

Step-by-step explanation:

We have given polynomial P(X)=x^3+kx^2+x+6

It is given that x+1 is factor of the polynomial

And we have to find the value of k

As x+1 is the factor of polynomial  so x+1 = 0 that is x = -1 will be the root of polynomial

So if we put x = -1 in the polynomial then the p(-1) will be zero

So 0=(-1)^3+k(-1)^2-1+6

k=-4

So the value of k will be -4

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Select all of the choices that are equal to (-5) – (-12).
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The base of the pyramid is a square what is the surface area if the pyramids height is 4 feet in the area of the base is 36 ft.?
KATRIN_1 [288]

Answer:

96 ft²

Step-by-step explanation:

The general formula for the surface area of a pyramid is:  

SA = \frac{1}{2}pl + B, were p = the perimeter of the base, l = the slant height and B = the area of the base

Since the area of the base is 36 ft², then each side is √36, or 6 ft. The perimeter is the sum of all the sides, so 6 x 4 = 24 ft.

Given the overall height of the pyramid is 4 feet, you can use the Pythagorean Theorem (a² + b² = c²) to find the slant height (hypotenuse) of the pyramid.  Using 3 feet for 'a' and 4 feet for 'b':

3² + 4² = c² or 9 + 16 = 25

25 = c² or c = 5

SA =  \frac{1}{2}(24)(5) + 36

SA = 60 + 36 = 96 ft²

8 0
3 years ago
Solve 0 = (x – 4)2 – 1 by graphing the related function.
fomenos

Answer:

Therefore, the solutions of the quadratic equations are:

x=5,\:x=3

The graph is also attached.

Step-by-step explanation:

The solution of the graph could be obtained by finding the x-intercept.

y=\left(x-\:4\right)^2-1

Finding the x-intercept by substituting the value y = 0

so

y=\left(x-\:4\right)^2-1

\:0\:=\:\left(x\:-\:4\right)^2\:-\:1        ∵ y = 0

\left(x-4\right)^2-1=0

\left(x-4\right)^2-1+1=0+1

\left(x-4\right)^2=1

\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

\mathrm{Solve\:}\:x-4=\sqrt{1}

\mathrm{Apply\:rule}\:\sqrt{1}=1

x-4=1

x=5

\mathrm{Solve\:}\:x-4=-\sqrt{1}

\mathrm{Apply\:rule}\:\sqrt{1}=1

x-4=-1

x=3

So, when y = 0, then x values are 3, and 5.

Therefore, the solutions of the quadratic equations are:

x=5,\:x=3

The graph is also attached. As the graph is a Parabola. It is visible from the graph that the values of y = 0 at x = 5 and x = 3. As the graph is a Parabola.

8 0
3 years ago
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