Given pair of lines are x² + 4xy + y² = 0
⇒ (y/x) ² + 4 y/x + 1 = 0
⇒ y/x = -4±2√3/2 = -2±√3,
∴ The lines y = (-2 + √3) x and y = (-2 - √3) x and x - y = 4 forms an equilateral triangle
Clearly the pair of lines x² + 4xy +y² = 0 intersect at origin,
The perpendicular distance form origin to x - y = 4 is the height of the
h = 2 √ 2
∵ Area of triangle = h²/√3 = 8/√3
So solve for the placeholder D
D/12=0.25
multiply both sides by 12 to clear fraction
12D/12=0.25 times 12
D(12/12)=3
D(1)=3
D=3
Answer:
17.89 :)
Step-by-step explanation: hii
I would say that the "n"th term of the sequence is 41, as the pattern increases by 10 every term.
