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Harman [31]
3 years ago
13

Consider the following quadratic equation x^2 =4x -5. How many solutions does it have?

Mathematics
2 answers:
aleksandrvk [35]3 years ago
5 0
The answer for your question is C.
Diano4ka-milaya [45]3 years ago
5 0

{x}^{2}  - 4x + 5 = 0
Can't be factored.

Answer is C.

Hope this helps. - M
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Laws of Sines with find the angle.
Jobisdone [24]
A divide by sin A = b divide by sin B
1. 27 divide by sin 68=22 divide by sin x
Sin x=sin 68 times 22 divide by 27
Sinx=0.65696
X=71.7 degrees
4 0
3 years ago
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Find <br> 2 numbers greater than 6 with the LCM 40
Katarina [22]
That is impossible but I did some math so there are 2 ways that will equal more than 40.

6.7×6.0=40.2
6.5×6.2=40.3

Hope this helps!
6 0
3 years ago
I thought of a number, added 4 5/7 to it, and got the number equal to the original one times 12. What was the original number?
Vilka [71]

Answer:

x=3/7

Step-by-step explanation:

x+4 5/7 = 12x

4 5/7 = 11x

x = 3/7

6 0
3 years ago
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What is the approximate value of sin B?
Jlenok [28]
The acronym for trigs is SOH CAH TOA
Sine means opposite divided by hypotenuse
So, let us find sine.
The opposie side is 16
The hypotenuse is 17.46
16/17.46
Use your calculator
The answer is ≈ 0.9164
6 0
3 years ago
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Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below
mafiozo [28]

Answer:

a) \bar X = 369.62

b) Median=175

c) Mode =450

With a frequency of 4

d) MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

<u>e)</u>s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

Replacing we got:

\bar X = 369.62

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Median=175

Part c

The mode is the most repeated value in the sample and for this case is:

Mode =450

With a frequency of 4

Part d

The midrange for this case is defined as:

MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

Part e

For this case we can calculate the deviation given by:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0
3 years ago
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