Answer:
Step-by-step explanation:
Let the two whole numbers be 5x and 2x then
by the question
5x - 2x = 33
3x = 33
x = 33/3
x = 11
Therefore the numbers are
- 5x = 5*11 = 55
- 2x = 2*11 = 22
hope it helps:)
Answer:
p=
Step-by-step explanation:
30100 have dogs, 18100 have cats.
The question simply asks for a union scenario thus the law of AND & OR is applicable.
Therefore:-Those who have both cats and dogs partially have cats.
Answer:
This equation has <u>No Solutions. </u>
Step-by-step explanation:
It is parrel because it has the same x. When equations have the same x it is always parrel or it always has no solutions.
<em>I hope it helps! Have a great day!</em>
<em>Lilac~ </em>
Step One
======
Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
Answer:
Equation: 15 - f = n
Answer: n = 9
Step-by-step explanation:
The question is asking to write the equation. The equation would be
"15 - f = n" where f shirts folded
n = shirts remaining to fold
Then the question has gave us the value of f and has told us to solve it. Below is the solution.
15 - 6 = n
=> n = 9
Therefore, there is 9 shirts remaining after 6 of them are folded.
What did we solve?
We wrote our equation and solved what was required in the question.
I hoped this helped.
If possible... May I have brainliest :)
