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skelet666 [1.2K]
3 years ago
6

I thought of a number, added 4 5/7 to it, and got the number equal to the original one times 12. What was the original number?

Mathematics
2 answers:
Travka [436]3 years ago
8 0

Answer:

3/7

Step-by-step explanation:

Vilka [71]3 years ago
6 0

Answer:

x=3/7

Step-by-step explanation:

x+4 5/7 = 12x

4 5/7 = 11x

x = 3/7

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If Jose has 10 cookies and he ate 5 how many cookies does he have left
MAVERICK [17]

Answer: five

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What does -3 2/3- (1 1/6)
ira [324]

Answer:

-29/6

Step-by-step explanation:

1 1/6=7/6

-3 2/3=-11/3

-11/3-7/6

-22/6-7/6=-29/6

5 0
3 years ago
Squareroot(y-1) + 3 = y
jek_recluse [69]
Note:xy means x times y and x(y) means the same thing

so
first we get rid of square root then
make the equation equal to zero becaues if
xy=0 then x or/and y=0



squareroot(y-1)+3=y

isolate the squareroot
subtrac 3 from boht sides

squareroot(y-1)=y-3

square both sides (since they are equal, you should be able to square both sides and still make it true)

(squareroot(y-1))^2=(y-3)^2
(y-1)=(y-3)(y-3)
y-1=y^2-6y+9
subtrac y from both sides
-1=y^2-7y+9
add 1 to both sides
0=y^2-7y+10
find what two number multiply to make 10 and add to get -7
the answer is -2 and -5

0=(y-5)(y-2)
therfore
y-5=0
and/or
y-2=0

therefor
y=5 or/and 2 might work
let's try out 2
square root(2-1)+3=2
square root(1)+3=2
1+3=2
false
so 2 doesn't work



let's try 5
squareroot(5-1)+3=5
squareroot(4)+3=5
2+3=5
5=5
true

y=5
7 0
3 years ago
What is the solution to this equation? x + (- 14) = 4. (A) x = 10. (B) x = - 10. (C) x = - 18. (D) x = 18
Vika [28.1K]
First, you want to get x by itself on one side. We write the equation as x-14=4. Since 14 is being subtracted from x, we add it to both sides to cancel it out, x-14+14=4+14 or x=18.

Your answer would be D.

4 0
3 years ago
Inequality n &lt; -5<br> HELPPP ASAPPP
ale4655 [162]

Answer:

please give me a brainless 0

Inequality :

α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x

The following is as far as I get:

α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x

(n−1)a−(⌊n÷m⌋×(a−b))≥x−α1

n−1−(⌊n÷m⌋×(a−b))≥x−α1a

n−(⌊n÷m⌋×(a−b))≥x−α1a + 1

Step-by-step explanation:

3 0
3 years ago
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