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2 years ago

The circle below is centered at (2, 3) and has a radius of 4. What is its equation?

Mathematics

1 answer:

disa [49]2 years ago

4 0

Answer:

Step-by-step explanation:

The standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$ where h and k are the center of the circle and r is the radius. Filling in:

$(x-2)^2+(y-3)^2=16$

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If the risk-free rate is 7 percent, the expected return on the market is 10 percent, and the expected return on Security J is 13

Lelu [443]

Answer:

0.02 or 2% = Beta

Step-by-step explanation:

Given that,

Risk-free rate = 7 percent

Expected return on the market = 10 percent

Expected return on Security J = 13 percent

Therefore, the beta of Security J is calculated as follows;

Expected return on Security J = Risk-free rate + Beta (Expected return on the market - Risk-free rate)

13 percent = 7 percent + Beta (10 percent - 7 percent)

0.13 - 0.07 = 0.03 Beta

0.06 = 0.03 Beta

0.06 ÷ 0.03 = Beta

0.02 or 2% = Beta

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2 years ago

Find the equation of the line using y=mx+b form thank you :)

Yuri [45]

The answer to the question

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3 years ago

Determine the next step for solving the quadratic equation by completing the square.

Studentka2010 [4]

Answer:

The solutions are $x=\frac{1+\sqrt{7}}{2}$ and $x=\frac{1-\sqrt{7}}{2}$

Step-by-step explanation:

we have

$0=-2x^{2}+2x+3$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$-3=-2x^{2}+2x$

Factor the leading coefficient

$-3=-2(x^{2}-x)$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$-3-0.5=-2(x^{2}-x+0.5^{2})$

$-3.5=-2(x^{2}-x+0.5^{2})$

Rewrite as perfect squares

$-3.5=-2(x-0.5)^{2}$

$7/4=(x-0.5)^{2}$

square root both sides

$x-0.5=(+/-)\sqrt{\frac{7}{4}}$

$x-\frac{1}{2}=(+/-)\frac{\sqrt{7}}{2}$

$x=\frac{1}{2}(+/-)\frac{\sqrt{7}}{2}$

$x=\frac{1+\sqrt{7}}{2}$

$x=\frac{1-\sqrt{7}}{2}$

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3 years ago

What is 2 + -5 - -13

rosijanka [135]

Answer:

10.

The answer is 10.

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2 years ago

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1 year ago