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3 years ago

Value of y when x = 0. -8× +8y =-16

Mathematics

2 answers:

Art [367]3 years ago

6 0

-8(0) =0
you divide 8y on both sides so y=-2

Rasek [7]3 years ago

4 0

Hello

I have done this before and Nothing further can be done.
Hope this helps

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3 years ago

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gtnhenbr [62]

Answer:

Option B is correct.

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Step-by-step explanation:

Given expression: $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$

Using exponents power:

$(ab)^n = a^nb^n$

$(a^n)^m = a^{nm}$

$a^m \cdot a^n = a^{m+n}$

Given: $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$

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Therefore, the expression which is equivalent to $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$ is, $\frac{81m^2 n^5}{8}$

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