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Sergio [31]
3 years ago
12

Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y = 2x2 + 4x –3

Mathematics
2 answers:
egoroff_w [7]3 years ago
8 0
Your vertex would be (-1,-5)
and your axis of symmetry is x=-1
Oksana_A [137]3 years ago
7 0

Answer:

Axis of symmetry is x=-1.

The vertex of the graph is (-1,-5).

Step-by-step explanation:

If a quadratic function is f(x)=ax^2=bx+c, then the axis of symmetry is

x=-\frac{b}{2a}

Vertex=(-\frac{b}{2a},f(-\frac{b}{2a}))

The given equation is

y=2x^2+4x-3

Here,

a=2,b=4,c=-3

The axis of symmetry is

x=-\frac{4}{2(2)}=-1

Substitute x=-1 in the given equation to find the y-coordinate of the vertex.

y=2(-1)^2+4(-1)-3

y=2-4-3

y=-5

Therefore, the vertex of the graph is (-1,-5).

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What is 314.16 rounded to the nearest hundredth
Galina-37 [17]

Since there is no number in the thousandths place which would make the number in the hundredths place round up or down, we keep the number the same:

314.16

Hope it helps! Good luck. :)

4 0
2 years ago
A) Is205 a term in the sequence 15.9, 13.......?<br> 10 15 22
ICE Princess25 [194]

Answer:

no

Step-by-step explanation:

as 205 is the term greater than the 1st term of AP and the difference is in decreasing order

6 0
3 years ago
Which of the following is equal to the rational expression when x does not equal 3 or 1 x^2-9/(x-1)(x-3)
yuradex [85]

Answer:

b.  \frac{x+3}{x-1}

Step-by-step explanation:

Given expression is:

\frac{x^{2}-9 }{(x-1)(x-3)}

Let us factorize the numerator using the formula:

a^{2} -b^{2} =(a+b)(a-b)

\frac{(x+3)(x-3)}{(x-1)(x-3)}

Since x ≠ 3, let us cancel the common factor x - 3 in the numerator and in the denominator.

So, \frac{x^{2}-9 }{(x-1)(x-3)} =\frac{x+3}{x-1}

7 0
3 years ago
Question 6 of 10
Margarita [4]

Answer: B. I and ll only

Step-by-step explanation:

7 0
2 years ago
12x+7&lt;-11 or 5x-8&gt;40
DaniilM [7]

Answer:

A

Step-by-step explanation:

Given

12x + 7 < - 11 or 5x - 8 > 40

Solve each inequality

12x + 7 < - 11 ( subtract 7 from both sides )

12x < - 18 ( divide both sides by 12 )

x < - \frac{3}{2}

OR

5x - 8 > 40 ( add 8 to both sides )

5x > 48 ( divide both sides by 5 )

x > \frac{48}{5}

Solution is

x < - \frac{3}{2} or x > \frac{48}{5} → A

6 0
2 years ago
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