Question

Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y = 2x2 + 4x –3

Answer 1

Your vertex would be (-1,-5)
and your axis of symmetry is x=-1

Answer 2

Answer:

Axis of symmetry is x=-1.

The vertex of the graph is (-1,-5).

Step-by-step explanation:

If a quadratic function is $f(x)=ax^2=bx+c$, then the axis of symmetry is

$x=-\frac{b}{2a}$

$Vertex=(-\frac{b}{2a},f(-\frac{b}{2a}))$

The given equation is

$y=2x^2+4x-3$

Here,

$a=2,b=4,c=-3$

The axis of symmetry is

$x=-\frac{4}{2(2)}=-1$

Substitute x=-1 in the given equation to find the y-coordinate of the vertex.

$y=2(-1)^2+4(-1)-3$

$y=2-4-3$

$y=-5$

Therefore, the vertex of the graph is (-1,-5).